Vector Proof: x x v = u x v = x x u

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SUMMARY

The discussion centers on proving the vector identity x x v = u x v = x x u, given the equation x + v = u. Participants explore the properties of the cross product, particularly the associative rule and the simplification of expressions involving vectors. The key approach involves substituting u into the equation and utilizing known properties of the cross product, leading to the conclusion that both sides of the equation are equal. The final simplification confirms that x x v equals u x v, reinforcing the relationship between the vectors.

PREREQUISITES
  • Understanding of vector operations, specifically the cross product.
  • Familiarity with vector addition and properties of vectors.
  • Knowledge of the associative rule in vector algebra.
  • Basic skills in simplifying algebraic expressions involving vectors.
NEXT STEPS
  • Study the properties of the cross product in depth, including the distributive and associative properties.
  • Learn about vector identities and their proofs in linear algebra.
  • Explore the geometric interpretation of the cross product and its applications in physics.
  • Practice solving vector equations and identities using various approaches and techniques.
USEFUL FOR

Students studying vector algebra, educators teaching linear algebra concepts, and anyone interested in mastering vector identities and their applications in mathematics and physics.

Jbreezy
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Homework Statement



If x + v = u
Prove x x v = u x v = x x u

The Attempt at a Solution



I don't even know where to start with this. I thought that magnitude of the resultant vector would have to be equal. So I started messing with each to see if I could find a pattern.

x x v = | x|| v| sin θ

This is a crap approach I can't find anything. Please give me a hint not the answer. I just can't seem to draw the information in my text together to give myself enough to show this. Thank you.
 
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Just use your definition of u in the equations, and simplify with known properties of the cross product.
It does not help to consider the magnitude of the vectors, as their "direction" has to fit, too.
 
Hi Jbreezy! :smile:

Are you allowed to use the associative rule, a x (b + c) = a x b + a x c ?

Or do you have to use coordinates?
 
I guess you are allowed to use whatever. I don't understand this problem at all.
 
ok, then what is x x (u - v) ? :wink:
 
0 vector? This is not anywhere in my eq. though. In terms of the original.
 
This was a good problem to make me feel like a monkey with a stick.

so, If x + v = u
Prove x x v = u x v = x x u

Sub in u.

x x v = (x + v ) x v = x x(x + v)

So when you distribute.

X x V = X x V + V x V = X x X + X x v

So, V x V = 0 , X x X = 0
So
X x V = X x V = X x V
Thanks
 
Hi Jbreezy! :smile:

(just got up :zzz:)

Yes, that's correct. :smile:

But it's a bit long-winded …

you could have done x x v = (x + v ) x v (because v x v = 0)

= u x v,​

or x x v - u x v = … (you finish it :wink:)
 

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