# Vector ramp question - time taken for object to slide down ramp

1. Jul 8, 2007

### avsj

1. The problem statement, all variables and given/known data

A 9.0 kg box is sliding down a smooth flat ramp which makes an angle of 24 degrees with the horizontal. If the coefficient of kinetic friction (μ) between the box and the ramp is 0.25, how long will it take the box to slide 2.0 m down the ramp froma standing start?

2. Relevant equations

Fg = mg
Ff = μFn
SOH/CAH/TOA

3. The attempt at a solution

Fg= 9.0 x 9.8 =88.2 N
From a vector diagram, I solved Fn using cos(24)x88.2= 80.6 N
Therefore, Ff = 0.24 (80.6) = 20.2 N
Fd (force down the ramp parallel to ramp) = sin(24) x 88.2 = 35.9

Fnet = 35.9 - 20.2 = 15.7 N

Now to solve d=vt.

d= 2.0m

but do i use 15.7 as my velocity or is it acceleration and if so, how should I approach the calculus? Or is the velocity also 15.7 m/s because it starts at rest. If so, i divide 2 by 15.7 and get a 0.13 but the answer in my text book is 1.5

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Jul 8, 2007

### chaoseverlasting

Everything up until here is correct. What you have is the net force being experienced by the block. Now, you know F=ma, so to find the acceleration you need to divide the force by the weight of the object.

Then you can solve for time using the acceleration and distance with equations of kinematics.

3. Jul 8, 2007

### avsj

Thanks a lot :D, ... but I haven't learned the equations of kinematics yet. Could you please tell me which ones are relevant?

Kinematics is our next unit, this is a 'brain buster' at the end of my current unit.

Thanks so much

4. Jul 8, 2007

### avsj

F= ma

15.7/9 = 1.7 acceleration

I tried d= (Vo + Vf)/2 x t

so 2 = 1.7/2 x t

t = 2.4