What is the Linear Velocity of a Location on Earth's Equator?

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SUMMARY

The linear velocity of a location on Earth's equator is calculated using the formula V = rw, where 'r' is the radius (3960 miles) and 'w' is the angular velocity (2π/24 radians/hour). The correct calculation yields a linear speed of approximately 1036.73 miles per hour. The method was confirmed by multiple users in the forum, with an alternative approach involving the circumference of the Earth (24881 miles) divided by the time (24 hours) also yielding the same result. The calculations were verified to be accurate, with minor decimal adjustments noted.

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  • Understanding of linear velocity and angular velocity concepts
  • Familiarity with the formula V = rw
  • Basic knowledge of Earth's dimensions, specifically the equatorial radius
  • Ability to perform calculations involving π (pi)
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  • Research the formula for calculating angular velocity in different contexts
  • Explore the concept of Earth's circumference and its implications for linear speed
  • Learn about the effects of Earth's rotation on time zones and geographical measurements
  • Investigate other methods for calculating velocity in circular motion
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Homework Statement



Earth rotates in on axis that goes through both the North and South Poles. It makes one complete revolution in 24 hours. If the distance from the axis to any location on the equator is 3960 miles, find the linear speed (in miles per hour) of a location on the equator.

Homework Equations



-None-

The Attempt at a Solution



I used the formula V=rw to find the linear velocity, and for 'r' I used 3960, and 'w' is used 2pi/24 for making one revolution per hour, so I simplified that down to pi/12 as angular velocity.

V=3960 x (pi/12 radians/hour)≈ 1036.73 miles/hour

Is this correct? It got checked in school, but I think I was off in the decimals or something. Is there something I did wrong or?

Thanks for any help!
 
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darshanpatel said:

Homework Statement



Earth rotates in on axis that goes through both the North and South Poles. It makes one complete revolution in 24 hours. If the distance from the axis to any location on the equator is 3960 miles, find the linear speed (in miles per hour) of a location on the equator.

Homework Equations



-None-

The Attempt at a Solution



I used the formula V=rw to find the linear velocity, and for 'r' I used 3960, and 'w' is used 2pi/24 for making one revolution per hour, so I simplified that down to pi/12 as angular velocity.

V=3960 x (pi/12 radians/hour)≈ 1036.73 miles/hour

Is this correct? It got checked in school, but I think I was off in the decimals or something. Is there something I did wrong or?

Thanks for any help!

Your method is correct, but check the numbers. 3690*3.14/12 is way off from your result.

ehild
 
I re-did it, and it came out to the same? Maybe it is something you inputted into your calc, I did pi/12 first then multiplied by 3960, and it came out to this?

I don't know what I am off at? I even did it the way you wrote it out, but it still worked?
 
Mark44 said:
Looks OK to me.

Thanks! :D
 
Sorry, I misread the number 3960:shy:. Your result is correct.

ehild
 
Another way to do this, though essentially the same, is to use "velocity= distance/time". You are given that the radius of the earth, at the equator, is 3960 so the circumference is 2\pi(3960)= 24881 miles. Divide that by 24 hours to get 1036.7 mph.
 

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