Velocity comparison -- Which thrown mass hits the ground first?

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The discussion revolves around the question of whether two objects thrown with different masses hit the ground simultaneously when air resistance is ignored. The original poster initially believed they would land at the same time but later questioned this conclusion. Participants emphasize the importance of understanding the physics involved and the need for the original poster to perform calculations to clarify their doubts. Forum rules prohibit providing solutions until the original poster has attempted the problem themselves. This ensures fairness and encourages learning through individual effort.
mathbrain9
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Homework Statement
A person is on a bridge is an object is thrown up at 10m/s with it going to the edge of the bridge. The person throws a 2nd object 10m/s down when the 1st is at the edge. Which makes it first?
Relevant Equations
v= d/t
On the test, I said they hit the ground simultaneously. However, that, in retrospect, doesn't seem to be the correct solution.
 
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Why don't you think that's right?
 
mathbrain9 said:
On the test, I said they hit the ground simultaneously. However, that, in retrospect, doesn't seem to be the correct solution.
What new perspective after the test made you change your mind? It is important that you figure this out because you don't want to second guess yourself when the next test comes around.
 
Does it specify whether to ignore air resistance?
 
What is the velocity of the first object at the instance you throw the second one downwards? Assume we are ignoring air resistance.

As I am unwell, I haven't done any calculations. But I think I know whether your first answer was right or wrong, and someone might do the sums for you eventually to check it.
 
DrJohn said:
someone might do the sums for you eventually to check it.
The forum rules prohibit any of us from doing those sums until the OP has done so. Meanwhile, the OP has not posted anything beyond the original post here. It would be improper to respond to "I thought the answer was X but now I am not sure" with a correct solution, a full mathematical treatment and the reasoning connecting the two. That would not be fair to the other posters who actually go to the trouble of showing their work.
 
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Thread 'Chain falling out of a horizontal tube onto a table'
My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

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