A particle with charge 9.42×10−8 C is moving in a region where there is a uniform magnetic field with a magnitude of 0.440 T in the +x-direction. At a particular instant of time the velocity of the particle has components -v_x = 1.70×10^4 m/s, -v_y = 3.19×10^4 m/s, v_z = 5.83×10^4 m/s.
a. What is the y-component of the force on the particle at this time?
b. What is the z-component of the force on the particle at this time?
F = q*v*B*sin theta
The Attempt at a Solution
In drawing the y and z components,
The y-component is pointing to the south, so the force’s y-component is pointing upward (positive?)?
The z-component is pointing upward out of the plane, so the force’s z-component is pointing north (positive?)?
As for calculating the individual force components, what else must be done aside from applying the F = q*v*B definition? (Just using F_y = v_y*B*q or F_z = v_z*B*q is incorrect, right?)
Thank you for any guidance.