Velocity correlation functions

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SUMMARY

The discussion centers on the derivation of the relationship between the mean square displacement and its time derivative in the context of Non-Equilibrium Statistical Mechanics, specifically referencing Zwanzig's work. The equation = ∫^{t}_{0}ds_{1}∫^{t}_{0}ds_{2} is provided, leading to the challenge of proving that ∂/∂t = 2∫^{t}_{0}ds. The fundamental theorem of calculus is identified as a key tool for this derivation, with emphasis on the application of the product rule to the integrals involved.

PREREQUISITES
  • Understanding of Non-Equilibrium Statistical Mechanics
  • Familiarity with the fundamental theorem of calculus
  • Knowledge of mean square displacement in statistical physics
  • Proficiency in handling double integrals and derivatives
NEXT STEPS
  • Study the application of the fundamental theorem of calculus in statistical mechanics
  • Explore the derivation of correlation functions in Non-Equilibrium Statistical Mechanics
  • Learn about the product rule in the context of multiple integrals
  • Investigate the implications of mean square displacement in physical systems
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Students and researchers in physics, particularly those focusing on statistical mechanics, as well as anyone seeking to deepen their understanding of correlation functions and their applications in non-equilibrium systems.

thrillhouse86
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Hi, I am going through Non Equilibrium Statistical Mechanics by Zwanzig and I can't follow, the step below:

I have the equation:
[tex] <x^{2}> = \int^{t}_{0}ds_{1}\int^{t}_{0}ds_{2}<v(s_{1})v(s_{2})>[/tex]

I can't show that:
[tex] \frac{\partial <x^{2}>}{\partial t} = 2 \int^{t}_{0}ds<v(s)v(t)>[/tex]

I'm sure that the answer lies with that fundamental theorem of calculus, but I can't show it. For one thing, do I apply the product rule to the two integrals above ?

Thanks
 
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call the upper indices (which are now both called t) a(t)=t and b(t)=t. Then use that the total derivative (well, total at least with respect to t) is d/dt=da/dt d/da+db/dt d/db.
 

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