Velocity of a ball (kg) droped from height (m)

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SUMMARY

A ball with a mass of 0.5 kg dropped from a height of 5 m will reach its greatest velocity just before impact due to gravitational acceleration. The force acting on the ball is calculated using the formula f = m * g, resulting in a force of 4.9 N. To determine the velocity, one can apply either the energy approach, equating potential energy to kinetic energy, or the kinematics approach using the time-independent equation. Both methods yield the same result for the velocity just before hitting the ground.

PREREQUISITES
  • Understanding of gravitational force (f = m * g)
  • Familiarity with potential and kinetic energy concepts
  • Knowledge of kinematics equations
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the conservation of energy principle in physics
  • Learn about time-independent kinematics equations
  • Explore the relationship between force, mass, and acceleration
  • Practice solving problems involving free fall and projectile motion
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of motion and energy conservation.

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Homework Statement



A ball of mass 0.5kg is dropped from a height of 5m what is the greatest velocity it will have just before hitting the ground?

Homework Equations



f=m*g
a= change in velocity/change in time


The Attempt at a Solution


m=.5kg
h=5m
a=9.8m/s

f=m*g
f= .5*9.8= 4.9N

I don't know what other equations to use to find velocity
 
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You can solve this one of two ways:

Energy approach: Energy at highest point is equal to the kinetic energy at the lowest point, since all potential energy is converted to kinetic as the ball is about to hit the ground.

Kinematics approach: Use the time independent kinematics equation.

Post if you need more specific guidance, because this is a relatively simple problem.
 
You can also use these equations together to solve:
d=0.5at2+v_{i}t+d_{i}
a=\frac{Δv}{Δt}.
 
Last edited:

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