Velocity of an ion given the potential difference it is accelerated through?

Click For Summary

Homework Help Overview

The discussion revolves around determining the velocity of an ion that has been accelerated through a potential difference of 7.0 kV before entering a magnetic field. The subject area includes concepts from electromagnetism and energy conservation in physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to find the mass of an unknown ion by first determining its velocity, expressing uncertainty about how to calculate this velocity with the given information. Some participants suggest using the relationship between kinetic energy and potential difference to derive the necessary equations.

Discussion Status

Participants have provided guidance on using conservation of energy principles to relate kinetic energy to the potential difference. There is an acknowledgment of assumptions that must be considered, such as the initial speed of the ion and the nature of the potential difference. The discussion appears to be moving towards a clearer understanding of the concepts involved.

Contextual Notes

There is a mention of specific values, such as the magnetic field strength (B=1.2 T), but the relevance of this information to the calculation of velocity is not fully explored. The original poster expresses a lack of familiarity with the concepts, indicating a need for foundational understanding.

runran
Messages
6
Reaction score
0
I'm trying to find the mass of an unknown ion and I think the equation I'm down to to find the mass only requires me to determine the velocity before I can calculate mass -- but I don't know how.

Could anyone help me out and direct me to an equation(s) that would help me find the velocity of some ion given that it was accelerated through a potential difference of 7.0 kV before entering a magnetic field? I'm not familiar with how to find the velocity with just that info. Don't know if this would be relevant, but B=1.2 T.

Sorry, I'm just clueless. (Don't even know if it is possible to calculate velocity with that... if it's not, please tell me ^^;) Thank you.
 
Last edited:
Physics news on Phys.org
runran said:
I'm trying to find the mass of an unknown ion and I think the equation I'm down to to find the mass only requires me to determine the velocity before I can calculate mass -- but I don't know how.

Could anyone help me out and direct me to an equation(s) that would help me find the velocity of some ion given that it was accelerated through a potential difference of 7.0 kV before entering a magnetic field? I'm not familiar with how to find the velocity with just that info. Don't know if this would be relevant, but B=1.2 T.

Sorry, I'm just clueless. (Don't even know if it is possible to calculate velocity with that... if it's not, please tell me ^^;) Thank you.

It's conservation of energy. What you need to know is that if a charge q is accelerated through a potential difference Delta V, then its kinetic energy is equal to simply the absolute value of q times (Delta V). So just set that equal to 1/2 mv^2 and this gives you an equation relating the mass and the speed.

EDIT: This assumes that the ion had no speed before being accelerated through the potential difference otherwise q Delta V is the change of kinetic energy. And it also assumes that potential of the plates is such that the ion is sped up, not slowed down. But those two assumptions are usually implicit in this type of problem.
 
Last edited:
nrqed said:
What you need to know is that if a charge q is accelerated through a potential difference Delta V, then its kinetic energy is equal to simply the absolute value of q times (Delta V). So just set that equal to 1/2 mv^2 and this gives you an equation relating the mass and the speed.
Just further to what nrqed said, you could work this fact out using the definition of voltage. When energy is conserved, work done = change in kinetic energy. Now, a definition of voltage is work done per unit charge, and mathematically is;

V = \frac{\text{work}}{q}

and this can be regarranged to obtain;

\text{work} = V\times q
 
Ok, thanks to you both =) I think I can hash out an answer now.
 
runran said:
Ok, thanks to you both =) I think I can hash out an answer now.
Well, here's the place to ask if you want something explained. :smile:
 

Similar threads

Replies
8
Views
2K
  • · Replies 27 ·
Replies
27
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 15 ·
Replies
15
Views
3K
Replies
9
Views
2K
Replies
8
Views
3K