Velocity of snapium given constant and weight

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SUMMARY

The discussion centers on calculating the launch speed of a 22 g plastic ball from a snapnium-loaded toy launcher, given a snaptastic constant of 4.6×104 N/m3 and a compression of 14 cm. Using the force law Fx=-q(x-xe)3 and the potential energy equation U(x)= (qx4)/4, the launch speed is determined to be 20 m/s through the application of conservation of total energy principles. The frictionless nature of the barrel simplifies the calculations, allowing for a direct application of energy conservation.

PREREQUISITES
  • Understanding of conservation of energy principles in physics
  • Familiarity with elastic potential energy equations
  • Knowledge of force laws, specifically cubic force relationships
  • Basic skills in unit conversion and dimensional analysis
NEXT STEPS
  • Study the derivation of elastic potential energy equations
  • Learn about the implications of frictionless systems in mechanics
  • Explore advanced applications of cubic force laws in materials science
  • Investigate the properties and applications of elastic materials like snapnium
USEFUL FOR

Students in physics, materials scientists, and engineers interested in mechanics and energy conservation principles will benefit from this discussion.

nlingraham
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Homework Statement



A snapnium-loaded toy launcher shoots a 22 g plastic ball. What is the launch speed if the snaptastic constant is 4.6×104 N/m3, with the units you found in part A, and the piece of snapnium is compressed 14 cm ? Assume the barrel is frictionless.

OTHER INFO:

A materials scientist comes up with a new elastic she calls "snapnium" that obeys the force law Fx=-q(x-xe)3, where xe is the equilibrium position of the end of the particular sample and q is the "snaptastic" constant. For simplicity, we'll let xe=0m . Then Fx=-qx3.

Homework Equations



U(x)= (qx4)/4

part A was finding units of q, which were N/m3

The Attempt at a Solution



The answer is 20 m/s, but I have no idea how to do it. Can someone explain to me what the process is to get to this answer?
 
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Use conservation of total energy.
 

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