Velocity of Water in 5 cm Tube: Solve Equation

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The discussion focuses on calculating the velocity of water in a 5 cm radius tube connected to a 1 cm radius tube, with water flowing at a rate of 10 liters/min. The pressure in the larger tube is 1×10^5 Pa, and the density of water is 1000 kg/m³. The correct approach involves using the flow rate equation: Flow rate = Velocity × Area, and ensuring consistent units by converting liters to milliliters and minutes to seconds. The final velocity calculation requires applying the area of the tube and the converted flow rate.

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1.A tube of radius 5 cm is connected to tube of radius 1 cm. Water is forced through the tube at a rate of 10 liters/min. The pressure in the 5 cm tube is 1×10^5 Pa. The density of water is 1000 kg/m3. Assume that the water is nonviscous and uncompressible.
What is the velocity of the water in the 5 cm radius tube?

2. Flow rate of liquid = Velocity X Area.
3. I believe the units are messing me up. I am not sure about the 10 liters/min. but my equation: 10 liters/min = (1000)x(5^2)(∏)(V) I am not coming up with the correct answers, and don't know if this is even close to the right equation. can someone point me in the right direction?
 
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The volume and area need to have the same length units.
 
convert the Liters into milliliters (L-mL) and use the conversion 1mL=1cm^3 than change minutes into seconds (1min=60sec)
 

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