Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Introductory Physics Homework Help
Velocity of wave along a rubber cord
Reply to thread
Message
[QUOTE="Gravitino22, post: 2718805, member: 227598"] ][h2]Homework Statement [/h2] You have a rubber cord of relaxed length x. It be- haves according to Hooke's law with a "spring con- stant" equal to k. You then stretch the cord so it has a new length equal to 2x. a) Show that a wave will propagate along the cord with speed v=[tex]\sqrt{\frac{2kx^{2}}{m}}[/tex] b) You then stretch the cord further so that the cord's length increases with speed v/3. Show that the wave will propagate during the stretching with a speed that is not constant: v(t)=[tex]\sqrt{\frac{kx^{2}}{m}(1+t\sqrt{\frac{2k}{9m}})(2+t\sqrt{\frac{2k}{9m}})}[/tex] [h2]Homework Equations[/h2] strings wave propagation speed: v=[tex]\sqrt{\frac{T}{u}}[/tex] hookes law: F=-kx Where T is tension and u is linear mass density [h2]The Attempt at a Solution[/h2] I have part A down My train of thought for part b is that if your length is changing at a constant rate of v/3 then so is thetension. The new tension would be given by T(t)=k(vt/3 -2x) and the linear mass density u(t)=m/(vt/3 +2x) i plugged those into the velocity equation but i didnt get the result...Iam sure i have to use differentials but iam not so good at that so if anyone can point me in teh right direction Thanks :)![/QUOTE] [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Introductory Physics Homework Help
Velocity of wave along a rubber cord
Back
Top