While the force was applied the RPM would continuously accelerate.drewman13 said:If there was a free-spinning effective weight of 20 lbs. at a 20" radius rotating at 180 rpm (15.7 fps?) and a force of 20 foot pounds was added, what would be the increase in velocity/speed?
Thanks for the reply... I guess I am not good at stating the problem, sorry for the lack of Engineering savvy...Assume for illustrative purposes that 20 pounds was added to the downstroke for a distance of one foot and was removed immediately after that one foot of distance. What I am, basically, looking for is the effect on one rotation. Specifically, I wish to find out what is the maximum gain in velocity from that one input of 20 foot lbs. for one revolution.Baluncore said:While the force was applied the RPM would continuously accelerate.
What is a “downstroke”? Is this a vertical axis or horizontal axis rotation?drewman13 said:Assume for illustrative purposes that 20 pounds was added to the downstroke for a distance of one foot and was removed immediately after that one foot of distance.
Thanks for that. I am sure you are right about SI units. My goal was just to see if I could get a hard number for mps or fps or rpm that resulted from the energy input to the vertical rotation. Assuming 180 rpm of original speed . (I added downstroke to imply vertical rotation). My degree is in Communications, (Graduated with Honors). I am much better with words than numbers, although Baluncore is correct that I made quite a few errors in my statement of the problem, including the OP Question. Currently, I am going through a health condition that reduces my cognitive skills. Originally, I attempted to become an Engineer but I quickly learned I am incapable of doing the math. This is one of the few places I can go with help on my inventions when I get stopped by the math. I, literally, would not have a clue as to do what you suggest, even though it is obviously the way to go. Let me know if you know of anywhere I can get something like this calculated, even if it is for a fee. Just need to keep it reasonable. Thanks.mfb said:You can calculate the moment of inertia of your object, and the kinetic energy as function of its speed follows from that. You have the initial energy, and you increase this by 20 pounds * 1 foot, so you know the new energy, which you can convert back to angular velocity.
You should consider using SI units, as imperial units are just a huge mess if you want to calculate anything.
The concept of velocity / speed loss by shifting to a larger radius is based on the principle of conservation of angular momentum. When an object moves in a circular path, it has a constant angular momentum. When the radius of the circular path is increased, the velocity of the object decreases in order to maintain the same angular momentum.
The radius of a circular path has an inverse relationship with the velocity of an object. As the radius increases, the velocity decreases and vice versa. This is because, for a given angular momentum, a larger radius requires a slower speed to maintain the same angular momentum.
Yes, the formula for calculating velocity / speed loss by shifting to a larger radius is v2 = v1 * (r1 / r2), where v1 is the initial velocity, v2 is the final velocity, r1 is the initial radius, and r2 is the final radius. This formula is based on the conservation of angular momentum principle.
No, the mass of the object does not affect the velocity loss when shifting to a larger radius. This is because the conservation of angular momentum principle applies to all objects, regardless of their mass. However, a heavier object may require more force to maintain the same angular momentum when shifting to a larger radius.
Yes, velocity / speed loss by shifting to a larger radius can be observed in various real-world situations, such as when a car takes a turn on a curved road. The car's speed decreases as it takes a wider turn, in order to maintain the same angular momentum. This phenomenon can also be observed in sports, such as ice skating, where the speed of the skater decreases as they shift to a larger radius curve.