Velocity with air resistance help

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Homework Help Overview

The discussion revolves around finding the velocity in a scenario involving air resistance, using the equations V=Vo+AT and A=G-KV. Participants are exploring how to manipulate these equations to isolate V.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss substituting A with G-KV in the equation and express challenges in isolating V due to its presence on both sides of the equation. There are inquiries about the steps taken to simplify the equation and the reasoning behind certain algebraic manipulations.

Discussion Status

Some participants have provided algebraic manipulations that appear to lead towards isolating V, while others are questioning the steps taken and seeking clarification on the reasoning behind these manipulations. The conversation reflects a collaborative effort to understand the problem better.

Contextual Notes

There is mention of the equation V=Vo+AT being derived from calculus for cases of constant acceleration, which raises questions about the assumptions made regarding acceleration in this context.

PHK
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I need to find the velocity with the following information. V=Vo+AT and A=G-KV

so how would i find what V equals from this: V=Vo+(G-KV)T
 
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Thats right. Is there something else to the question too? What velocity do you have to find?
 
there's nothing else to the problem. i plugged in G-KV in for A in the first equation but now i have V=Vo+(G-KV)T. and i want to find velocity, but can't because there is velocity in the equation. so i want to know how to simplify the equation so i get V only on one side.
 
did anyone figure it out yet?
 
PHK said:
did anyone figure it out yet?

V=Vo+(G-KV)T

V = Vo + GT - KVT

V + KVT = Vo + GT

etc...
 
I think this is right:

V=Vo+(G-KV)T = Vo+TG-TKV
V-Vo=TG-TKV
V-Vo+TKV=TG
V+TKV=TG+Vo
V(1+TK)=TG+Vo

V=(TG+Vo)/(1+TK)[EDIT]oops, looks like learningphysics beat me to it.
 
"Replacement by an equal expression" is a procedure that is used a lot.
( like you replaced the "A" by "G-kV" )
"Multiplication, Distributive" ( Phoenix line 1 ) and
its inverse , "Factoring" (Phoenix line 5) are the basis of proportion.
When you add the negative of some term to both sides
(so that term cancels the original term on that side)
and/or divide both sides by the same factor
(so as to "move the factor to the other side")
... there's always more than one path that you can take
notice how Phoenix "undid" in line 4 , what he had done in line 2 ...
it is okay to take more steps, so long as you keep the goal in mind.
 
thanks the equation works. i got one question tho. how did you get from this V+TKV=TG+Vo
to this V(1+TK)=TG+Vo?
 
PHK said:
I need to find the velocity with the following information. V=Vo+AT and A=G-KV

so how would i find what V equals from this: V=Vo+(G-KV)T
Where did you get the equation V = Vo + AT? This equation is derived from calculus for the special case of constant acceleration. In your case, the acceleration is changing with speed, and is therefore not constant.
 
  • #10
PHK said:
thanks the equation works. i got one question tho. how did you get from this V+TKV=TG+Vo
to this V(1+TK)=TG+Vo?

he factored out the V... try multiplying out: V(1+TK)... what do you get?
 

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