MHB Verification of Limit Using Taylor Expansion: x-ln(1+x)/x^2 = 1/2

AI Thread Summary
The limit of the expression (x - ln(1+x))/x^2 as x approaches 0 is confirmed to be 1/2. The calculation involves using the Taylor expansion of ln(1+x), which simplifies the limit evaluation. By substituting the series expansion into the limit, it is shown that the terms converge to 1/2 as x approaches 0. The discussion emphasizes the importance of understanding series in evaluating limits. Overall, the verification of the limit is accurate and clearly demonstrated.
Fernando Revilla
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I quote a question from Yahoo! Answers

Use series to evaluate lim x->0 (x-ln(1+x)/x^2)?
I got 1/2. Could anyone please verify my answer. I am still very confused about series. Please show how you got your answer.
Thanks

I have given a link to the topic there so the OP can see my response.
 
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Certainly, the limit is $1/2:$
$$\lim_{x\to 0}\frac{x-\log (1+x)}{x^2}=\lim_{x\to 0}\frac{x-\left(x-\frac{x^2}{2}+o(x^2)\right)}{x^2}\\
=\lim_{x\to 0}\left(\frac{1}{2}-\frac{o(x^2)}{x^2}\right)= \frac{1}{2}-0=\frac{1}{2}$$
 
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