Verifying the Fourier Series is in Hilbert Space

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SUMMARY

The discussion centers on verifying that the Fourier Series is a valid element of Hilbert Space by demonstrating that the integral of the product \( f^{*}f \) converges. The expression \( f^{*}f = a_0^2 + a_1^2 \cos^2 x + b_1^2 \sin^2 x + a_2^2 \cos^2 2x + b_2^2 \sin^2 2x + ... \) converges if the coefficients \( a_n \) and \( b_n \) are bounded by 1 in absolute value. The validity of this approach is confirmed, as it aligns with Parseval's theorem, which establishes the orthogonality and completeness of the Fourier basis in Hilbert Space.

PREREQUISITES
  • Understanding of Fourier Series and their coefficients
  • Knowledge of Hilbert Space concepts
  • Familiarity with Parseval's theorem
  • Basic calculus for convergence analysis
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  • Study the implications of Parseval's theorem in functional analysis
  • Explore the properties of orthogonal functions in Hilbert Spaces
  • Learn about convergence criteria for series in mathematical analysis
  • Investigate applications of Fourier transforms in signal processing
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Mathematicians, physicists, and engineers interested in functional analysis, particularly those working with Fourier Series and their applications in Hilbert Space.

kostoglotov
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The text does it thusly:

Xj2z1Cr.jpg


imgur link: http://i.imgur.com/Xj2z1Cr.jpg

But, before I got to here, I attempted it in a different way and want to know if it is still valid.

Check that [itex]f^{*}f[/itex] is finite, by checking that it converges.

[tex]f^{*}f = a_0^2 + a_1^2 cos^2x + b_1^2sin^2x + a_2^2cos^22x + b_2^2sin^22x + ...[/tex]

should converge provided the a's and b's are both less than 1 in absolute value.

Is this also a valid way to show that our Fourier Series is an okay vector to work with?
 
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kostoglotov said:
show that our Fourier Series is an okay vector to work with
What is it you want to show ? Orthogonality is OK, and normality is OK (provided you use the correct normalization constants). Completeness ? For all functions you can write the recipe to get the Fourier transform.

So yes, the Fourier basis is OK.
 
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