(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An electron moving horizontally at 2.50 x 10^{6}m/s enters a 150 N/C electric field exactly half way between two horizontal parallel plates and follows a parabolic path downwards. Both plates are 14 cm long and spaced 10 cm apart. Determine the vertical displacement of the e- as it travels between the plates.

2. Relevant equations

E = F_{e}/q , F=ma , E_{p}= mgh

3. The attempt at a solution

I found F_{e}by E/q and got 2.40 x 10^{-17}J. then I plugged the values into F=ma and found the acceleration to be 2.63 x 10^{13}m/s^{2}. I then divided the velocity by acceleration and found time to be 9.49 x 10^{-18}s. I am now unsure how to find the vertical distance. I used E_{p}= mgh but got a very large value, so I think that is wrong. Did I make a mistake earlier or should I be using a different equation?

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# Homework Help: Vertical Displacement of Electron (Millikan's Oil Drop)

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