- #1
honeybee63
- 1
- 0
Homework Statement
An electron moving horizontally at 2.50 x 106 m/s enters a 150 N/C electric field exactly half way between two horizontal parallel plates and follows a parabolic path downwards. Both plates are 14 cm long and spaced 10 cm apart. Determine the vertical displacement of the e- as it travels between the plates.
Homework Equations
E = Fe/q , F=ma , Ep = mgh
The Attempt at a Solution
I found Fe by E/q and got 2.40 x 10-17 J. then I plugged the values into F=ma and found the acceleration to be 2.63 x 1013 m/s2. I then divided the velocity by acceleration and found time to be 9.49 x 10 -18 s. I am now unsure how to find the vertical distance. I used Ep = mgh but got a very large value, so I think that is wrong. Did I make a mistake earlier or should I be using a different equation?
Last edited: