- #1

honeybee63

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## Homework Statement

An electron moving horizontally at 2.50 x 10

^{6}m/s enters a 150 N/C electric field exactly half way between two horizontal parallel plates and follows a parabolic path downwards. Both plates are 14 cm long and spaced 10 cm apart. Determine the vertical displacement of the e- as it travels between the plates.

## Homework Equations

E = F

_{e}/q , F=ma , E

_{p}= mgh

## The Attempt at a Solution

I found F

_{e}by E/q and got 2.40 x 10

^{-17}J. then I plugged the values into F=ma and found the acceleration to be 2.63 x 10

^{13}m/s

^{2}. I then divided the velocity by acceleration and found time to be 9.49 x 10

^{-18}s. I am now unsure how to find the vertical distance. I used E

_{p}= mgh but got a very large value, so I think that is wrong. Did I make a mistake earlier or should I be using a different equation?

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