A 70.0 kg person steps through the window of a burning building and drops to a rescue net held 8.00 m below. If the surface of the net is 1.40 m above the ground, what must be the value of the spring constant for the net so that the person just touches the ground when the net stretches down.
How do I find the velocity of the man falling?
The Attempt at a Solution
Eg + Ee + Ek = Eg' + Ee' + Ek'
Eg + Ek = Ee'
mgh + .5mV2 = .5kx
(70)(9.8)(9.4) + .5(70)V2 = 0.5k(1.4)2