How Far Does an Object Fall in the Third Second of Vertical Motion?

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To determine how far an object falls during the third second of vertical motion, the acceleration due to gravity is 9.8 m/s². The discussion highlights the importance of using the correct formulas and understanding the timing of the third second, which begins at 2 seconds and ends at 3 seconds. The answer is calculated to be 24.5 meters, but participants emphasize the need to show effort and follow homework guidelines when seeking help. The conversation encourages users to structure their questions using a specific template to facilitate better assistance. Understanding the timing and applying the correct equations are crucial for solving the problem accurately.
jefflee0510
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Missing homework template due to originally being posted in other forum.
(Neglect air resistance in all cases)
An object falls down from the top of a high overhanging cliff. How far does it fall in the third second of its motion?

I don't know which formula to use. I know that a=9.8ms^-2 and t=3s I think.
Apparently the answer is 24.5m. But I don't know how to work it out. :C
 
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jefflee0510 said:
in the third second
When does the third second of the fall begin? tinitial = ?
When does the third second end? tfinal = ?
 
Hi jefflee0510 and welcome to Physics Forums!

Please post your homework and homework-like questions in the homework forums. You are also required to show some effort when posting in these forums. Simply saying "I have no idea where to begin is not good enough". See our homework guidelines.
 
Hi Jef, welcome to the homework part of PF :)

The idea here is that you use the homework template
1. Homework Statement
2. Homework Equations
3. The Attempt at a Solution​
And the helpers are are obliged to protest if parts are missing. That explains the reception you got from Oro.

As to your statement: I don't know.. -- That can be solved if you pick something that you think is reasonable (e.g. from here) and start to work on the solution by filling in things from 1.) in the template.

In the mean time, Bystander has already helped you on you way !
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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