Vertices of triangle, multi-problems

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Homework Help Overview

The discussion revolves around the properties of a triangle defined by its vertices A(2a,0), B(2b,0), and C(0,2). Participants are exploring the equations of the sides of the triangle and the equations of the medians, with a focus on understanding the concept of medians in relation to the midpoints of the sides.

Discussion Character

  • Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the equations of the sides of the triangle and express confusion regarding the definition and calculation of medians. There is an exploration of the relationship between the vertices and the midpoints of the sides, with questions about whether the medians refer to these midpoints.

Discussion Status

Some participants have provided hints and clarifications regarding the definition of a median and the importance of midpoints in the context of the triangle. There is an ongoing exploration of the correct equations and interpretations, with no explicit consensus reached yet.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the depth of exploration or the methods discussed. There is an acknowledgment of potential algebraic errors in previous attempts, which may affect the understanding of the problem.

rocomath
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Vertices of triangle ABC are A(2a,0), B(2b,0), C(0,2).

a) Find the equations of the sides (check, did that)

AB: y=0
AC: x+ay=2a
BC: x+by=2b

I'm having trouble with b)

Show that the equations of the medians are: x+(2a-b)y=2a, x+(2b-a)y=2b, 2x+(a+b)y=2(a+b)

Ok, they're not referring to the midpoints of AB, AC, and BC? I think that's where my mistake is. The median is point of intersection where a line intersects each line at each line's midpoint and meets at a common center point inside the triangle?
 
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Part of your objective is to find the midpoint of each side because that is an essential component of Median of a Triangle. The point in the interior of the triangle at which the medians intersect is of no concern in the answer.
 
rocomath said:
Vertices of triangle ABC are A(2a,0), B(2b,0), C(0,2).

a) Find the equations of the sides (check, did that)

AB: y=0
AC: x+ay=2a
BC: x+by=2b

I'm having trouble with b)

Show that the equations of the medians are: x+(2a-b)y=2a, x+(2b-a)y=2b, 2x+(a+b)y=2(a+b)

Ok, they're not referring to the midpoints of AB, AC, and BC? I think that's where my mistake is. The median is point of intersection where a line intersects each line at each line's midpoint and meets at a common center point inside the triangle?

No. A "median" of a triangle is the line segment from one vertex to the midpoint of the opposite side. For example, the midpoint of AB is (a+b, 0) and C is (0,2). What is the equation of that line?
 
Your answer to part a) ...

... isn't quite right. Hint: What is the y-int of lines connecting A and C ? A and B?
 
Sorry, I meant B and C?
 
tmclary said:
... isn't quite right. Hint: What is the y-int of lines connecting A and C ? A and B?

tmclary said:
Sorry, I meant B and C?
?

The equations given were AC: x+ay=2a and BC: x+by=2b with A= (2a,0), B= (2b, 0), and C= (0, 2). When x= 2a, the first equation gives 2a+ ay= 2a or y= 0 and when x= 0 it gives ay= 2a or y= 2. When x= 2b, the second equation gives 2b+ by= 2b or y= 0 and when x= 0 it gives by= 2b so y= 2. Exactly what is wanted.
 
D'oh

Yup, yup and yup. Sheesh, the careless algebra mistakes I can make are embarrassing. thanks H.O.V.
 

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