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Vertices of triangle ABC are A(2a,0), B(2b,0), C(0,2).
a) Find the equations of the sides (check, did that)
AB: y=0
AC: x+ay=2a
BC: x+by=2b
I'm having trouble with b)
Show that the equations of the medians are: x+(2a-b)y=2a, x+(2b-a)y=2b, 2x+(a+b)y=2(a+b)
Ok, they're not referring to the midpoints of AB, AC, and BC? I think that's where my mistake is. The median is point of intersection where a line intersects each line at each line's midpoint and meets at a common center point inside the triangle?
a) Find the equations of the sides (check, did that)
AB: y=0
AC: x+ay=2a
BC: x+by=2b
I'm having trouble with b)
Show that the equations of the medians are: x+(2a-b)y=2a, x+(2b-a)y=2b, 2x+(a+b)y=2(a+b)
Ok, they're not referring to the midpoints of AB, AC, and BC? I think that's where my mistake is. The median is point of intersection where a line intersects each line at each line's midpoint and meets at a common center point inside the triangle?