Very Simple Eigenvalue Calculation Need explanation please

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Homework Help Overview

The discussion revolves around calculating the eigenvalues of a 2x2 matrix. Participants are exploring the concept of eigenvalues and the process of determining them through the determinant of the matrix.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the method of calculating eigenvalues by setting the determinant of (A - λI) to zero. There is confusion regarding why certain values are not considered eigenvalues, specifically questioning the values 5 and 0 versus the actual eigenvalues of 2 and 3.

Discussion Status

The discussion is active, with participants questioning assumptions about eigenvalue calculations. Some have provided guidance on determining the determinant and setting it to zero, while others reflect on their algebraic mistakes and clarify their understanding of the eigenvalue process.

Contextual Notes

There is a mention of algebraic errors in the calculations, which may have contributed to misunderstandings about the eigenvalues. Participants are encouraged to revisit their calculations and assumptions.

bmb2009
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Homework Statement



Calculate the eigenvalues of the matrix
5 2
-3 0



Homework Equations





The Attempt at a Solution



Ok we were taught that eigenvalues were calculated by taking the determinant( A - λI) = 0. So just subtract a "λ" value from the diagnol entries of the given matrix... so why aren't the eigenvalues 5 and 0? Please help me understand why the e values are 2 and 3?
 
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bmb2009 said:

Homework Statement



Calculate the eigenvalues of the matrix
5 2
-3 0



Homework Equations





The Attempt at a Solution



Ok we were taught that eigenvalues were calculated by taking the determinant( A - λI) = 0. So just subtract a "λ" value from the diagnol entries of the given matrix... so why aren't the eigenvalues 5 and 0? Please help me understand why the e values are 2 and 3?

What is the determinant of the matrix A - λI? What is the equation you get when you set this determinant to zero?

Besides: see what you get when you try to solve the equation Ax = 5x; that will tell you why 5 is not an eigenvalue.
 
bmb2009 said:
Ok we were taught that eigenvalues were calculated by taking the determinant( A - λI) = 0. So just subtract a "λ" value from the diagnol entries of the given matrix... so why aren't the eigenvalues 5 and 0? Please help me understand why the e values are 2 and 3?
I have to ask: Why do you think the eigenvalues would be 5 and 0?
 
I just realized that I butchered my algebra and now see that det(A- xI) = 0

(5-x)(-x) - (-6) = x^2 -5x + 6 = 0
(x-2) (x-3) = 0
x=2,3

Thanks for reminding me though appreciate it!
 

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