Very simple problem about wavelength, just a double check on work

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Homework Help Overview

The discussion revolves around a problem involving the calculation of wavelength and frequency from a given wavenumber of 1200 cm-1. The subject area pertains to wave properties in physics, particularly in the context of spectroscopy.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between wavenumber and wavelength, with some confirming the calculations presented. There is a question raised about the definition of wavenumber, specifically whether it is defined as 1/λ or 2π/λ.

Discussion Status

The discussion includes confirmations of the calculations, with some participants expressing agreement on the correctness of the approach. However, there is an ongoing exploration of the definition of wavenumber and its implications for the calculations.

Contextual Notes

There is a note regarding the assumption that the wavenumber is in a vacuum, as well as the potential variability in the definition of wavenumber depending on the context.

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Homework Statement



radiation with a frequency of 1200cm^-1, calculate the wavelength in meters and the frequency in hertz



Homework Equations



wavenumber = 1/λ

freq = c/λ



The Attempt at a Solution



1200cm^-1 = 1/λ

λ = 8.33*10^-6 m

freq = (3.0 * 10^8)/(8.66*10^-6) = 3.6*10^13 Hz
 
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vande060 said:

Homework Statement



radiation with a frequency of 1200cm^-1, calculate the wavelength in meters and the frequency in hertz

Homework Equations



wavenumber = 1/λ

freq = c/λ

The Attempt at a Solution



1200cm^-1 = 1/λ

λ = 8.33*10^-6 m

freq = (3.0 * 10^8)/(8.66*10^-6) = 3.6*10^13 Hz
Hi vande060.

Looks good to me, & I'm a spectroscopist.

(I assume that's 1200 cm-1 in a vacuum.)
 
vande060 said:

Homework Statement



radiation with a frequency of 1200cm^-1, calculate the wavelength in meters and the frequency in hertz
Do you mean wavenumber?

Homework Equations



wavenumber = 1/λ

freq = c/λ



The Attempt at a Solution



1200cm^-1 = 1/λ

λ = 8.33*10^-6 m

freq = (3.0 * 10^8)/(8.66*10^-6) = 3.6*10^13 Hz
I think that's right. :approve: But realize that depending on the context, wavenumber sometimes is defined as 1/λ and sometimes defined as 2π/λ. The above looks right to me assuming that you are using the wavenumber = 1/λ definition, and assuming that you mean the wavenumber is 1200 cm-1.
 
Thanks, both of you
 
vande060 said:

radiation with a frequency of 1200cm^-1

if its wave number, then your answer is correct?
 

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