Vibrating String under Gravity: Solutions & Considerations

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SUMMARY

The discussion focuses on the equations of motion for a vibrating string under gravity, specifically addressing the effects of transverse damping and driving forces. The derived equation of motion is τ0∂2xψ - b∂txψ + ∂xF(x,t) = λ0∂2tψ, where τ0 represents tension and λ0 denotes linear mass density. The participant contrasts the parabolic solution obtained for a string in equilibrium under gravity with the expected hyperbolic cosine solution for a hanging cable, concluding that the discrepancy arises from the loading conditions on the cable. The distinction between uniform loading and loading due to the cable's weight is clarified, leading to the identification of parabolic and catenary solutions.

PREREQUISITES
  • Understanding of differential equations in physics
  • Familiarity with concepts of tension and linear mass density
  • Knowledge of damping forces and their effects on motion
  • Basic principles of static equilibrium in mechanics
NEXT STEPS
  • Study the derivation of the catenary equation and its applications
  • Explore the effects of transverse damping on vibrating systems
  • Investigate the differences between parabolic and hyperbolic solutions in mechanics
  • Learn about the mathematical modeling of strings and cables under various loading conditions
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Physicists, engineers, and students studying mechanics, particularly those interested in the dynamics of vibrating strings and cables under gravitational forces.

Gear300
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Consider a string vibrating (with small amplitude) against a transverse damping force b(∂ψ/∂t) that acts per unit length. Also consider the effect of a transverse driving Fy that acts per unit length.

The equation of motion I got was
τ02xψ - b∂txψ + ∂xF(x,t) = λ02tψ ,
where τ0 is the tension along the string and λ0 is the linear mass density.

Now consider a string of length L in equilibrium under gravity.

The equation of motion thus becomes
τ02xψ - mg = 0 .
The solution I get from this is parabolic, whereas from what I remember, the form for a hanging chain/cable/wire/etc... is a hyperbolic cosine (cosh). I was wondering whether I made a mistake somewhere, or that this is a result of the small amplitude condition.
 
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Gear300 said:
The solution I get from this is parabolic, whereas from what I remember, the form for a hanging chain/cable/wire/etc... is a hyperbolic cosine (cosh). I was wondering whether I made a mistake somewhere, or that this is a result of the small amplitude condition.

If you assume the loading on the cable is uniform in the horizontal direction, the solution is a parabola.

If you assume the loading comes from the weight of the cable, the loading per horizontal distance is NOT uniform, because it depends on the slope of the cable at each point. For that case, the solution is a catenary.

http://mathworld.wolfram.com/Catenary.html
 
AlephZero said:
If you assume the loading on the cable is uniform in the horizontal direction, the solution is a parabola.

If you assume the loading comes from the weight of the cable, the loading per horizontal distance is NOT uniform, because it depends on the slope of the cable at each point. For that case, the solution is a catenary.

http://mathworld.wolfram.com/Catenary.html

Thanks. I just realized that might have been the case. My force was not done correctly.
 

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