Vibration/Centrifugal Force Question

[svansvan]

Hello

I am making a vibration project which requires me to mount eccentric weights on both sides of an electric motor. I must submit the "generated force(in Kg)" by this motor.The RPM of motor = 1000
Total weight on both sides of the motor = 16.8Kg (8.4Kg on both sides)
The radius(distance from the center of the shaft to the end of the weight) = 103 mmWhat will be creation of Centrifugal force when this motor is run at 1000 RPM ??Dhiraj

 

[Dr.D]

Where are you going to locate these weights? At what radius?

Think about the problem of tension in a string holding a rock and being swung in a circle. Your problem is similar.

 

[Dale]

I must submit the "generated force(in Kg)" by this motor.

This doesn't make sense. "Generated force" is measured in Newtons, not kilograms.

 

[Dr.D]

Dale, it does if you work in the bastard (old) metric system that measured forces in kilograms. This is exactly analogous to measuring mass in pounds. I certainly don't recommend this, but I have to recognize it when I see it happening.

 

[Dale]

So is a "1 kg force" equal to 1 N or 9.8 N?

 

[Dr.D]

Dale, it is the later, 1 kgf = 9.807 N.

 

[Dr.D]

Dale, there is also the perhaps more common gram-force, such that 1 gf = 980.7 dynes.

 

[svansvan]

take a look at this video. The motor has to be used like this. To vibrate certain appratus
also look at this image for weight placement

gthanks