Vibration/Centrifugal Force Question

Click For Summary

Discussion Overview

The discussion revolves around calculating the centrifugal force generated by an electric motor with eccentric weights mounted on both sides. Participants explore the implications of the motor's RPM, the total weight, and the radius of the weights in relation to the centrifugal force produced during operation.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant seeks to calculate the centrifugal force generated by a motor running at 1000 RPM with a total weight of 16.8 kg mounted eccentrically.
  • Another participant draws an analogy to the tension in a string holding a rock swung in a circle, suggesting a similar approach to the problem.
  • A participant questions the terminology of "generated force" being expressed in kilograms, asserting that force should be measured in Newtons.
  • There is a discussion about the use of the old metric system where force is sometimes expressed in kilograms, with one participant acknowledging this practice despite recommending against it.
  • Clarification is provided that 1 kgf is equivalent to approximately 9.807 N, which is contested by another participant who asks for confirmation on this conversion.
  • Additional information is shared regarding gram-force and its conversion to dynes, indicating a broader discussion on force measurement units.
  • A participant references a video and an image to illustrate the intended use of the motor and the placement of weights, indicating practical application considerations.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the terminology of force measurement, with some advocating for the use of kilograms while others emphasize the standard of Newtons. The calculation of centrifugal force remains unresolved, with differing views on how to approach the problem.

Contextual Notes

There are unresolved assumptions regarding the definitions of force and the context in which the weights are mounted. The discussion also reflects a mix of modern and historical measurement practices, which may influence participants' understanding of the problem.

svansvan
Messages
2
Reaction score
0
Hello

I am making a vibration project which requires me to mount eccentric weights on both sides of an electric motor. I must submit the "generated force(in Kg)" by this motor.The RPM of motor = 1000
Total weight on both sides of the motor = 16.8Kg (8.4Kg on both sides)
The radius(distance from the center of the shaft to the end of the weight) = 103 mmWhat will be creation of Centrifugal force when this motor is run at 1000 RPM ??Dhiraj
 
Physics news on Phys.org
Where are you going to locate these weights? At what radius?

Think about the problem of tension in a string holding a rock and being swung in a circle. Your problem is similar.
 
svansvan said:
I must submit the "generated force(in Kg)" by this motor.
This doesn't make sense. "Generated force" is measured in Newtons, not kilograms.
 
Dale, it does if you work in the bastard (old) metric system that measured forces in kilograms. This is exactly analogous to measuring mass in pounds. I certainly don't recommend this, but I have to recognize it when I see it happening.
 
So is a "1 kg force" equal to 1 N or 9.8 N?
 
Dale, it is the later, 1 kgf = 9.807 N.
 
Dale, there is also the perhaps more common gram-force, such that 1 gf = 980.7 dynes.
 

take a look at this video. The motor has to be used like this. To vibrate certain appratus
also look at this image for weight placement
xx.JPG
gthanks
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 17 ·
Replies
17
Views
7K
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 74 ·
3
Replies
74
Views
10K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 9 ·
Replies
9
Views
5K