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I was having a conversation with a physicist on Facebook (author of a book I rather enjoyed - "Users guide to the universe"), and he let the conversation end without my question ever being fully answered. Perhaps someone here can help explain this to me.
I'll paste the entire conversation, but the executive summary is:
Hawking radiation is caused by virtual particles coming into existence near the event horizon of a black hole. The virtual particles come in matter / anti matter pairs, and in some way result in the eventual evaporation of the black hole. I had been under the impression this was accomplished because the antimatter particle would have a stronger attraction to the black hole, and would annihilate, while the matter particle would be ejected. This would result in a net loss of mass in the black hole.
The problem is, I can't remember why the antimatter particle would be the one attracted, and if it is random chance with equal opportunity which falls in, the black hole would gain mass as often as it would lose mass and would never actually evaporate.
My question is, by what mechanism does Hawking Radiation cause the mass of the black hole to decrease over time
Transcript (optional reading):
#
Richard Henretta
You confuse me, sir...
Quote
[But as luck would have it, the electron falls beneath the event horizon of the black hole and is gone forever. The positron, (like every malfunction on the holodeck ever), goes from being virtual to real, and flies off into the cosmos.]
I thought the particle gets emitted, and the anti-particle falls into the black hole annihilating, thus resulting in the eventual evaporation of the black hole? If the electron falls and the positron is emitted wouldn't the mass of the black hole increase over time?
#
A User's Guide to the Universe
Either one can fall in. The universe doesn't distinguish between the two, so it's random luck which one gets eaten. In practice (in my example), the positron will hit an electron eventually and annihilate, producing photons. More commonly, the "pair" will be two photons (since photons are their own anti-particles), one of which will fall in, and one of which will escape.
#
Richard Henretta
Black hole evaporation can't happen then if it is random luck.
If the antiparticle falls in, and the particle escapes: the mass of the black hole will decrease
If the particle falls in, and the antiparticle escapes: the mass of the black hole will increase
In any case with photons, no change to mass occurs (which I still don't understand since photons have energy and energy equates into mass)
If we are talking random chance, then the top two cases will happen approximately the same number of times, resulting in no change to the mass.
I remember reading somewhere an explanation on why the antimatter particle had more attraction than the matter particle, but for the life of me I can't remember what it was. In fact, based on my rudimentary understand of physics, I see no reason why that would be the case anyway. So, do black holes not evaporate over time?
#
A User's Guide to the Universe
No no. The masses of both are positive. Forget about the particle that falls in. The particle that escapes carries energy away, and since ultimately energy borrowed from the vacuum must be paid back, that energy comes from the mass-energy of the black hole, causing it to evaporate.
#
Richard Henretta
But then by what mechanism is it paid back? If the energy of both particles is positive, and one particle falls into the black hole, how does that decrease the mass of the black hole?
Also, if anyone is wondering the context of this conversation, it stemmed from this article:
http://io9.com/5731463/are-virtual-particles-for-real
I'll paste the entire conversation, but the executive summary is:
Hawking radiation is caused by virtual particles coming into existence near the event horizon of a black hole. The virtual particles come in matter / anti matter pairs, and in some way result in the eventual evaporation of the black hole. I had been under the impression this was accomplished because the antimatter particle would have a stronger attraction to the black hole, and would annihilate, while the matter particle would be ejected. This would result in a net loss of mass in the black hole.
The problem is, I can't remember why the antimatter particle would be the one attracted, and if it is random chance with equal opportunity which falls in, the black hole would gain mass as often as it would lose mass and would never actually evaporate.
My question is, by what mechanism does Hawking Radiation cause the mass of the black hole to decrease over time
Transcript (optional reading):
#
Richard Henretta
You confuse me, sir...
Quote
[But as luck would have it, the electron falls beneath the event horizon of the black hole and is gone forever. The positron, (like every malfunction on the holodeck ever), goes from being virtual to real, and flies off into the cosmos.]
I thought the particle gets emitted, and the anti-particle falls into the black hole annihilating, thus resulting in the eventual evaporation of the black hole? If the electron falls and the positron is emitted wouldn't the mass of the black hole increase over time?
#
A User's Guide to the Universe
Either one can fall in. The universe doesn't distinguish between the two, so it's random luck which one gets eaten. In practice (in my example), the positron will hit an electron eventually and annihilate, producing photons. More commonly, the "pair" will be two photons (since photons are their own anti-particles), one of which will fall in, and one of which will escape.
#
Richard Henretta
Black hole evaporation can't happen then if it is random luck.
If the antiparticle falls in, and the particle escapes: the mass of the black hole will decrease
If the particle falls in, and the antiparticle escapes: the mass of the black hole will increase
In any case with photons, no change to mass occurs (which I still don't understand since photons have energy and energy equates into mass)
If we are talking random chance, then the top two cases will happen approximately the same number of times, resulting in no change to the mass.
I remember reading somewhere an explanation on why the antimatter particle had more attraction than the matter particle, but for the life of me I can't remember what it was. In fact, based on my rudimentary understand of physics, I see no reason why that would be the case anyway. So, do black holes not evaporate over time?
#
A User's Guide to the Universe
No no. The masses of both are positive. Forget about the particle that falls in. The particle that escapes carries energy away, and since ultimately energy borrowed from the vacuum must be paid back, that energy comes from the mass-energy of the black hole, causing it to evaporate.
#
Richard Henretta
But then by what mechanism is it paid back? If the energy of both particles is positive, and one particle falls into the black hole, how does that decrease the mass of the black hole?
Also, if anyone is wondering the context of this conversation, it stemmed from this article:
http://io9.com/5731463/are-virtual-particles-for-real