- #1

bchat112000

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A volleyball is spiked so that its incoming velocity of +4.1 m/s is changed to an outgoing velocity of -18 m/s. The mass of the volleyball is 0.44 kg. What impulse does the player apply to the ball?

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- Thread starter bchat112000
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- #1

bchat112000

- 6

- 0

A volleyball is spiked so that its incoming velocity of +4.1 m/s is changed to an outgoing velocity of -18 m/s. The mass of the volleyball is 0.44 kg. What impulse does the player apply to the ball?

- #2

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[itex]\vec{J}\equiv \int_{t_0}^{t_f}dt' \vec{F}_{net} (t')[/itex]

From Newton's second law, the impulse is also equal to the change of momentum.

[itex]\vec{J}=\vec{p}_f -\vec{p}_i =m\vec{v}_f -m\vec{v}_i[/itex]

If we know [itex]m[/itex],[itex]\vec{v}_f[/itex], and [itex]\vec{v}_i[/itex], we have all the information needed to figure out the impulse.

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