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Voltage difference of the wing of an airplane in Earth's magnetic fiel

  1. Jun 20, 2013 #1
    1. The problem statement, all variables and given/known data

    5.jpg

    2. Relevant equations

    B=F/|q0|vsinθ

    V=IR

    3. The attempt at a solution

    V=500m/h = 8.05m/h = 223m/s
    L=35m
    B=0.50gauss

    0.50g=F/|q0|*223m/s*sin90
     
  2. jcsd
  3. Jun 20, 2013 #2

    haruspex

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    Wouldn't V = vBL sin θ be more to the point?
    I guess you mean v=500mph = 805kph = 223m/s
     
  4. Jun 21, 2013 #3

    rude man

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    You need to change gauss to tesla.
    Also, none of your proffered equations are directly relevant. Consider haruspex's suggestion.
     
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