Voltage Div. Homework: Find Voltage Drop Across 2K Ohm Resistor

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Homework Help Overview

The discussion revolves around a circuit analysis problem involving voltage division to determine the voltage drop across a 2k ohm resistor. The original poster references a previous calculation related to a 10k ohm resistor and provides a voltage result of 250V from that part.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of the total resistance (R_T) and its implications for the voltage division method. Questions arise regarding the accuracy of the resistance values and the configuration of resistors in the circuit.

Discussion Status

Participants are actively questioning the calculations and assumptions made regarding the total resistance and the arrangement of resistors. Some guidance is provided regarding the configuration of resistors, but there is no explicit consensus on the correct approach or values.

Contextual Notes

There are indications of potential miscalculations in determining R_T, and participants are clarifying the arrangement of resistors, particularly noting that some resistors are in parallel while others are in series. The original poster's results and the book's answers are being compared, highlighting discrepancies.

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Homework Statement


see attached for circuit

from your result from part b, use voltage division to find the voltage drop across the 2k ohm resistor. my result from b was 250V

part b question was voltage drop across 10K resistor

Homework Equations





The Attempt at a Solution


R_T=5k ohms

v=V_2k/V_T = 100v but the answer is 50V?

Thanks
 

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What does R_T stand for?
 
total of the other resistors
 
You must have calculated RT wrong.

I get the book answer.
 
Don't forget the 5kΩ resistor.
 
can you tell me how please, I got 5k for Rt
 
The 6kΩ, 18kΩ, and 9kΩ resistors are all in parallel with each other.

That combination is in series with the 5 kΩ and 2 kΩ resistors.

The above is what I would call RT, judging by the way you used RT.
 

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