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Voltage, electricity and transformers question?

  1. Feb 25, 2010 #1
    1. The problem statement, all variables and given/known data

    An electric power plant generates electricity @ 22 kV
    and 100 A. The voltage is stepped up to 240 kV before
    being transmitted to a city 15 km away over a copper
    wire that has a radius of 2 mm. Energy is lost in heating
    the wire during transmission. If the transformer is 95%
    efficient, and the price of electricity is 15¢/kWh, How
    much money is saved per day by stepping the voltage up
    instead of transmitting it at the original voltage?



    2. Relevant equations
    P1 = Ip^2 R
    P2 = Is^2 R

    Specific resistance of copper = pi d^2 R /4 L , where d = 4x10-3 m (?)
    Sp.resistance of copper = 1.7x120^-4 ohm-m (?)

    3. The attempt at a solution
    No definitive idea of how to solve it unfortunately :/
     
    Last edited: Feb 25, 2010
  2. jcsd
  3. Feb 25, 2010 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Welcome to PF!

    Hi Arkane1337! Welcome to PF! :smile:

    (try using the X2 tag just above the Reply box :wink:)

    Show us how far you've got, and where you're stuck, and then we'll know how to help! :smile:
     
  4. Feb 25, 2010 #3
    So far I have a few variables mapped out, and apparently, the first equation and 'part' figured out:

    I = 100A, Vp = 22kV, r =2mm,

    Equationing:
    Part 1
    VsIs = VpIp(.95)

    Is = [(22)(100)(.95)] / [240kV]

    = 8.708A (secondary transformer output current apparently)

    Part2
    Power Loss with/out step ups: (?)
    P1 = Ip2*R
    P2 = Is2*R

    The specific resistance of copper is also 1.678 * 10-6 ohm-cm apparently

    I'm not sure if what I have so far is right or truly relevant, nor what I should do next. A friend of mine claims that he found the answer to be $14,497,500 saved, but I'm not sure if that is correct. (Haven't gotten a chance to take a look at his actual work either.)
     
    Last edited: Feb 25, 2010
  5. Feb 26, 2010 #4

    epenguin

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    Homework Helper
    Gold Member

    You've got V (RMS I presume) and I of the generator. That can tell you the total power, which is consumed - turned into heat - between the city, the wires and the transformer when there is one.

    5% of that is power is consumed by the transformer. So you can work that out straightaway.

    For the power consumed in the lines it would be more convenient to use V which you already have than I which you never need to know here. From the V's that you are given you can already work out the ratio of what you waste in the wires in the two situations. You can already see that bit is very in favour of upping the voltage.

    For the actual amount I think though you do have to work out the resistance of the wire.

    Expect the low voltage one to waste more than 5% otherwise it's pointless.

    I notice that they haven't included in the problem any step-down transformers at the other end of the wire. There will be several of them and at least two steps down before the current arrives in the houses. A lot of transformers, presumably consuming more energy than the generator one? Never thought of it before. So when they say money saved does the generator companies costs end when the electricity arrives at the city?

    But you are not asked that.

    Also I thought the big transformers at the generator end did quite a bit better than 95%, very efficient.

    The academic excercise is some use for some principles, but an engineer along here to explain some nitty gritties of power transmission would be additionally educative.
     
    Last edited: Feb 27, 2010
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