Voltage in a Non-Ideal Battery

[sweetdion]

Homework Statement

Given the following circuit:

What is the actual voltage provided to the circuit by the non-ideal battery if the internal resistance r = 0.50 ohms and the internal emf is 9.0 volts?

A. 9.8 V
B. 8.5 V
C. 9.0 V
D. 8.4 V
E. 8.8 V

Homework Equations

V=IR

The Attempt at a Solution

First, do I determine the current in the circuit, I? Then,
Total resistance in circuit if battery was ideal = 9/I
9/I - .5= 9/I-.5 ohms. At I amps, the voltage would be (I amps x 9/I-.5) = how ever many V...

How do I calculate I?

 

[tiny-tim]

Hi sweetdion!

Find I by first finding the equivalent resistance (including r) …

then the effective (actual) voltage is the potential difference across that dotted box, which is V minus … ?