The drawing shows two fully charged capacitors (C1 = 2.00[tex]\mu[/tex]F, q1 = 6.00[tex]\mu[/tex]C; C2 = 8.00[tex]\mu[/tex]F, q=12.0[tex]\mu[/tex]C). The switch is closed, and charge flows until equilibrium is reestablished (i.e., until both capacitors have the sam voltage across their plates). Find the resulting voltage across either capacitor. **i have attached a jpg of the drawing 2. Relevant equations q=CV , 1/Cs=1/C1+1/C2 3. The attempt at a solution I know the capacitors are in series so I have attempted to find the resultant capacitance, as well as working from the voltages calculated via q=CV. However, I have been unable to find the answer listed in the back o the text (1.80 V). Please help point me in the correct direction.