Voltage potential due to 2 charges

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SUMMARY

The discussion focuses on calculating the electric potential at points a and b due to two charges, Q1 = +1.60 nC and Q2 = -1.60 nC. The correct formula used is V = kQ/r, where k is Coulomb's constant (8.99e9 N m²/C²). The initial calculation yielded an incorrect potential of 191700 V due to a numerical error in the conversion of nanocoulombs. The correct interpretation of nanocoulombs as x10-9 is crucial for accurate results.

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  • Understanding of electric potential and Coulomb's law
  • Familiarity with the concept of nanocoulombs
  • Basic algebra for manipulating equations
  • Knowledge of the significance of Coulomb's constant (k)
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bobby3280
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Homework Statement


Find the potential at points a and b in the diagram for charges Q1 = +1.60 nC and Q2 = -1.60 nC.

I know b is 0
physics.gif



Homework Equations



V = kQ/r

The Attempt at a Solution



I tried this using the equation and got

8.99e9 * [( +1.60e-6 / .05) + ( -1.60e-6 / .15 ) ] = 191700 V but this isn't right any suggestions??
 
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bobby3280 said:

Homework Statement


Find the potential at points a and b in the diagram for charges Q1 = +1.60 nC and Q2 = -1.60 nC.

I know b is 0
physics.gif



Homework Equations



V = kQ/r

The Attempt at a Solution



I tried this using the equation and got

8.99e9 * [( +1.60e-6 / .05) + ( -1.60e-6 / .15 ) ] = 191700 V but this isn't right any suggestions??

If its nancoulombs as the question suggests then you've just made a numerical error in the solution. Nano = x10-9
 
Wow how'd I miss that thanks!
 

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