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Voltage, Resistance, and Current chart

  1. Dec 1, 2012 #1
    1. The problem statement, all variables and given/known data
    I have a chart here:
    2vv6cma.jpg


    2. Relevant equations

    I = V/R

    3. The attempt at a solution

    [itex]I_{1} = \frac{24.0 V}{8.0 V} = 3.00 A[/itex]

    [itex]R_{1} = \frac{8.00 V}{3.00 A} = 2.67 Ω[/itex]


    I'm stuck at how to progress on filling this up any further. Any hints?

    Thanks :)
     
  2. jcsd
  3. Dec 1, 2012 #2

    gneill

    User Avatar

    Staff: Mentor

    You've specified V/V for I1. That's not Ohm's law.

    Start by using KVL around the loop, treating the R2||R3 combination as a single item (maybe call it "Rp"); what's the potential drop across it?
     
  4. Dec 1, 2012 #3
    Oops, my bad, should have noticed that.

    What's KVL?
     
  5. Dec 1, 2012 #4

    gneill

    User Avatar

    Staff: Mentor

    KVL is Kirchhoff's voltage law; the sum of the potential changes around a closed path is zero.
     
  6. Dec 1, 2012 #5
    Oh, ok, we haven't covered that yet in my text.
     
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