 #1
bonbon22
 92
 5
 Homework Statement:

https://www.ocr.org.uk/Images/171728unith55602exploringphysicssampleassessmentmaterials.pdf
question 3
 Relevant Equations:
 V=IR
As you can see when the switch is open it measures the voltage across the battery or emf I am assuming when calculating the internal resistance when the switch is closed voltage is 6 right so the internal resistance is 6/2 =3 which is not correct. answer is A
Does this mean when the switch is ("closed" edit ) then the voltmeter now measures the terminal pd which is the voltage across the cirucuit less its internal resistance , so in this case the voltmeter measures the voltage of the resistor in series with the internal resistance , which does give me the right answer of 1.5. Why is this the case ? why does the switch change what the volt meter is measuring when closed.
Does this mean when the switch is ("closed" edit ) then the voltmeter now measures the terminal pd which is the voltage across the cirucuit less its internal resistance , so in this case the voltmeter measures the voltage of the resistor in series with the internal resistance , which does give me the right answer of 1.5. Why is this the case ? why does the switch change what the volt meter is measuring when closed.
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