- #1

bonbon22

- 92

- 5

- Homework Statement
- https://www.ocr.org.uk/Images/171728-unit-h556-02-exploring-physics-sample-assessment-materials.pdf

question 3

- Relevant Equations
- V=IR

As you can see when the switch is open it measures the voltage across the battery or emf I am assuming when calculating the internal resistance when the switch is closed voltage is 6 right so the internal resistance is 6/2 =3 which is not correct. answer is A

Does this mean when the switch is ("closed" edit ) then the voltmeter now measures the terminal pd which is the voltage across the cirucuit less its internal resistance , so in this case the voltmeter measures the voltage of the resistor in series with the internal resistance , which does give me the right answer of 1.5. Why is this the case ? why does the switch change what the volt meter is measuring when closed.

Does this mean when the switch is ("closed" edit ) then the voltmeter now measures the terminal pd which is the voltage across the cirucuit less its internal resistance , so in this case the voltmeter measures the voltage of the resistor in series with the internal resistance , which does give me the right answer of 1.5. Why is this the case ? why does the switch change what the volt meter is measuring when closed.

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