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Volume by Shells, continually getting wrong answers

  1. Oct 20, 2011 #1
    1. The problem statement, all variables and given/known data
    y = x^(1/3) - 2

    Find volume across the x-axis on 8 <= x <= 27 using the Method of Shells


    2. Relevant equations
    V = 2pi * Integral(r * h) from a -> b


    3. The attempt at a solution

    Let x = (y + 2)^3

    Let h = (y +2)^3 // Set height

    Let r = y // Set radius

    Attempt:

    2pi * Integral(y(y+3)^3 dy) from 0 to 1 // Integrate in terms of y

    I multiplied (y+3)^3 out, and combined with y for:

    2pi * Integral(y^4 + 6y^3 + 12y^2 + 8y dy) from 0 to 1

    =

    2pi ((y^5)/5 + ((3/2)*y^4) + (4y^3) + (4y^2)) from 0 to 1

    I then calculate F(1) - F(0) and get (194/10)pi = (97/5)pi.

    However, the correct answer in the book is (38/5)pi.

    I also tried u-substitution and still got (97/5)pi.

    Please help... this is extremely frustrating for me. I have been working really hard at finding volumes for the last two weeks and still continue to get most of my answers wrong. I've been to tutoring, my professor's office hours multiple times, and now I'm here. I just don't see what I'm doing wrong. I have an exam tomorrow morning and feel like I'm going to flunk it even though I've put in more than my fair share of studying.

    I did set the radius and height correctly, right? If so, what is going on?
     
  2. jcsd
  3. Oct 20, 2011 #2

    Mark44

    Staff: Mentor

    What's the exact wording in this problem? Is the graph of your function revolved around the x-axis?
     
  4. Oct 20, 2011 #3

    Mark44

    Staff: Mentor

    This (above) is incorrect. The width of your shell is 27 - (y + 2)3
    I get this answer.
     
  5. Oct 20, 2011 #4
    Thanks, I've got it now too, but how am I supposed to know when to subtract the width/height from x without looking at a graph???

    I just did a very similar problem (y = 8 - x^3), subtracted from x for the height, and got the wrong answer. I got the right answer when I didn't subtract h from x.

    I'm so confused
     
  6. Oct 20, 2011 #5

    Mark44

    Staff: Mentor

    You probably won't know. That's why you should always draw the graph.
     
  7. Oct 20, 2011 #6
    Thanks a lot. I was making this a lot harder for myself than I needed to.
     
  8. Oct 20, 2011 #7

    Mark44

    Staff: Mentor

    The first thing I did was to sketch a graph of the curve, and then to sketch a drawing of the rotated solid object. From the drawing it was obvious that the width of the shell was 27 - (y + 2)2.

    When you have expressions that represent length of some sort, if it's a vertical length, you want yupper - ylower. If it's a horizontal length, you want xright - xleft. Having a drawing helps you figure this out, so that you have the right signs for your lengths.
     
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