1. The problem statement, all variables and given/known data Suppose that the volume transport associated with the wind-driven circulation's western boundary current (such as the Gulf Stream) is 50 x 10^6 m^3/second. Assume that this volume transport is carried in a current of uniform speed which is 50 km wide and 1 km thick. Calculate the average velocity of the current. 2. Relevant equations Q = v * A (volumetric flow rate = velocity*area) 3. The attempt at a solution Reworking the equation Q = v*A to solve for velocity yields the equation, v = Q/A. Area has been converted from km to meters. So, velocity = (50 x 10^6 m^3/sec) / (50,000,000 m^2) = 1 meter/second. So, the answer I've found is a velocity of one meter per second. This is a graduate level course, however, so I am not sure that this correct. The math is not wrong, though; could it be my approach?