Volume of a Sphere: Solve with Calculus & Integration

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The discussion centers on deriving the volume of a sphere using calculus and integration, specifically the formula V = (4/3)πr^3. Participants express confusion over the book's explanation, particularly regarding the concept of cross-sectional areas and the multiplication by π. The method involves visualizing the sphere as a series of vertical disks, where the volume of each disk is calculated as its area times its thickness, dx. Clarification is sought on how the radius of the disks relates to the overall radius of the sphere. Understanding these concepts is crucial for successfully applying integration to find the volume of a sphere.
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Homework Statement



Show that the volume of a sphere of radius r is

V = (4/3)πr^2

Homework Equations



calculus, integration

The Attempt at a Solution



I have the solution in the book but it's confusing me, I'll attach a picture.

2m7zp88.jpg


So I get lost where it starts talking about a cross-sectional area all of a sudden multiplying by ∏. What's going on here?!
 
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What's the area of a circle of radius r? What if the radius is y instead of r?
 
Feodalherren said:

Homework Statement



Show that the volume of a sphere of radius r is

V = (4/3)πr^2
Probably a typo - the volume is (4/3)##\pi r^3##.

Feodalherren said:

Homework Equations



calculus, integration

The Attempt at a Solution



I have the solution in the book but it's confusing me, I'll attach a picture.

2m7zp88.jpg


So I get lost where it starts talking about a cross-sectional area all of a sudden multiplying by ∏. What's going on here?!
The book is using disks that are oriented vertically (the x-axis intersects each disk perpendicularly). The volume of such a disk is its area times its thickness, dx.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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