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Volume of figure revolving around line

  1. Apr 25, 2013 #1
    1. The problem statement, all variables and given/known data

    A represents the 1st quadrant area bounded by f(x)=e^(-tanx), y=.01, y=.09, and the y-axis. Write an integral expression for the volume of the figure that results from revolving A around the line x=30.

    2. Relevant equations



    3. The attempt at a solution

    So, I know that I have to integrate sideways. To do that, I tried putting the equation y=e^(-tanx) into x= form:

    y=e^(-tanx)
    -tanx=lny
    tanx=-lny
    x=invtan(-lny)

    So now, I'm not sure what to to. I think you have to integrate sideways somehow and then revolve it around the verticle line x=30...?
     
    Last edited by a moderator: Apr 26, 2013
  2. jcsd
  3. Apr 25, 2013 #2

    Mark44

    Staff: Mentor

    You don't have to "integrate sideways." Have you drawn a sketch of the region A, and of the solid that is formed? You can integrate using washers (horizontal disks of thickness Δy) or shells (with each of thickness Δx. If you use shells, you'll need two integrals, because the upper boundary changes from a horizontal line to the curve f(x) = e-tan(x).
     
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