Volume of intersection of spheres

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SUMMARY

The discussion focuses on calculating the volume of intersection between two spheres, each with a radius of 2, where the center of each sphere lies on the surface of the other. Participants suggest using the washer method for integration, specifically rotating the curve defined by y = (4 - (x + 1)^2)^(1/2) around the x-axis. The correct approach involves integrating the area of circular cross-sections, confirming that the volume can be doubled due to symmetry. The final volume of the intersection is confirmed to be 8/3 * π.

PREREQUISITES
  • Understanding of calculus, specifically integration techniques.
  • Familiarity with volumes of revolution and the washer method.
  • Knowledge of the geometric properties of spheres and their intersections.
  • Ability to work with functions and their transformations in a Cartesian coordinate system.
NEXT STEPS
  • Study the washer method in detail for calculating volumes of revolution.
  • Learn about the geometric properties of sphere intersections.
  • Practice integration techniques involving square roots and polynomial functions.
  • Explore applications of calculus in three-dimensional geometry.
USEFUL FOR

Students in calculus courses, particularly those studying volumes of solids of revolution, as well as educators looking for examples of sphere intersection problems.

icosane
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Homework Statement


Find the volume of the intersection of two spheres of radius 2, give that the center of each sphere lies on the surface of the other.

The Attempt at a Solution



I was trying to do this problem with volumes of revolution. I drew two circles, one with a center at -1, the other with a center at 1. I found the point of intersection on the y-axis to be + and - root3. I was going to use the washer method, rotating the line y = (4-(x+1)^2)^(1/2) over the x-axis but I can't integrate that expression. I'm also unsure if that would even give the correct answer. Any tips on how to approach the problem? This is for a calc 2 class btw, so it shouldn't be especially difficult.
 
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icosane said:

Homework Statement


Find the volume of the intersection of two spheres of radius 2, give that the center of each sphere lies on the surface of the other.

The Attempt at a Solution



I was trying to do this problem with volumes of revolution. I drew two circles, one with a center at -1, the other with a center at 1. I found the point of intersection on the y-axis to be + and - root3. I was going to use the washer method, rotating the line y = (4-(x+1)^2)^(1/2) over the x-axis but I can't integrate that expression. I'm also unsure if that would even give the correct answer. Any tips on how to approach the problem? This is for a calc 2 class btw, so it shouldn't be especially difficult.

Woops just realized that I would be taking the integral of y^2 so that square root sign doesn't mess up my ability to integrate. Still though, will I get the correct answer if I find that volume and multiply it by two? My concern is that I'm overlooking something about the geometry of the intersection. Like it seems like the volume would be a sum of the area of ellipses, not circles. Yet I don't know how I would end up with an elliptical equation from two intersecting spheres? Help please.
 
What range of x are you using when integrating using washers under the curve y=(4-(x+1)^2)^(1/2)? If you've got the right range, yes then you can just double that volume. The cross-sections of your volume perpendicular to the x-axis are circles, not ellipses. I don't think you are missing anything.
 
Dick said:
What range of x are you using when integrating using washers under the curve y=(4-(x+1)^2)^(1/2)? If you've got the right range, yes then you can just double that volume. The cross-sections of your volume perpendicular to the x-axis are circles, not ellipses. I don't think you are missing anything.

The range I used is just x = 1 to 0...
 
I used x=0 to x=1, but yes, that seems fine.
 
Did anyone try this and get 8/3 * pi ??
 
icosane said:
Did anyone try this and get 8/3 * pi ??

That's not what I get. Can you show how you got that?
 

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