Hey guys I'm stuck on this problem. Its an easy one but I need some help.. It's asking for the volume of the solid obtained by rotating the region bounded by y=x^2, y=4, x=0 about the line x= -2 using the shell method. I got the answer correct using the disk method (answer is 136 pi/3).. With shell method I get integral 2pi (2+x) (4-x^2) dx from x=0 to x=2 which is 88pi/3. Can someone please help me out of this mess?