Volume of water needed in a 40x6x3.5m lock with a 700T ship

[davekardle]

What's the volume of water required inside the lock if...

Homework Statement

The dimension of the lock is:40 long x 3.5 height x 6 width
allowing 0.5 height.

The ship weights 400T plus 300T(LOAD)
total= 700T

whats the amount of water used per lock allowing allowing 0.5 m from the height?

What if the ship empties its load on the lock ? the density of the load is 755kg/m^3.

Homework Equations

Archimedes principle
Mass of water displaced

The Attempt at a Solution

Mass of water displaced by the boat mass = 700T
VOLUME = 700M^3
Total volume inside the lock allowing 0.5

(3x40x6)m^3 - 700M^3

Is that correct ?

How about if the ship empties its load on the lock ?

 

[rude man]

Homework Statement

The Attempt at a Solution

Mass of water displaced by the boat mass = 700T
VOLUME = 700M^3
Total volume inside the lock allowing 0.5

(3x40x6)m^3 - 700M^3

Is that correct ?
Yes.

How about if the ship empties its load on the lock ?

The new displaced volume of water will be how much? So the level of the lock rises by how much?

 

[SteamKing]

Duplicate posting in several other forums.