Volume Shell Method: Setup & Evaluation

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SUMMARY

The forum discussion focuses on the application of the shell method to calculate the volume of a solid generated by revolving the region defined by the equation y = √x around the y-axis. The correct integral setup is V = 2∏∫(x)(√x)dx, evaluated from the interval [0, 9], leading to a volume of 972π/5. A common mistake identified was using the incorrect upper limit of integration, which was initially set to 8 instead of the correct value of 9.

PREREQUISITES
  • Understanding of the shell method for volume calculation
  • Familiarity with integral calculus
  • Knowledge of the function y = √x
  • Ability to evaluate definite integrals
NEXT STEPS
  • Review the shell method for calculating volumes of revolution
  • Practice evaluating definite integrals with varying limits
  • Explore graphical representations of functions to better understand regions of integration
  • Learn about common mistakes in volume calculations and how to avoid them
USEFUL FOR

Students studying calculus, particularly those focusing on volume calculations using the shell method, as well as educators seeking to clarify common misconceptions in integral evaluation.

chapsticks
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Homework Statement



Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the y-axis.
y = √x

Homework Equations



V=2∏∫p(x)h(x) dx
a=0
b=8

The Attempt at a Solution



V=2∏∫(x)(√x)dx
a=0 b=8
=2∏∫(x)3/2dx
=[(4∏/5)x5/2]8
V= when I do this my answer is wrong and too big
 

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chapsticks said:

Homework Statement



Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the y-axis.
y = √x

Homework Equations



V=2∏∫p(x)h(x) dx
a=0
b=8

The Attempt at a Solution



V=2∏∫(x)(√x)dx
a=0 b=8
=2∏∫(x)3/2dx
=[(4∏/5)x5/2]8
V= when I do this my answer is wrong and too big

It looks to me like the interval over which you should be integrating is [0, 9], not [0, 8]. Except for that, I don't seen anything wrong. I get an answer of 972\pi/5 for the volume.
 
Wow I should have paid close attention the graph is too small haha thank you.
 

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