A thermometer has a quartz body within which is sealed a total volume of 0.400 cm3 of mercury. The stem contains a cylindrical hole with a bore diameter of 0.10 mm. How far does the mercury column extend in the process of rising from 10°C to 94°C? Neglect any change in volume of the quartz. delta V= B*V0*delta T I thought this problem would be pretty simple. I have the equation from my textbook along with the value for B so I just plugged them in: delta V= (182*10^-6)(0.400cm3)(84)= 0.0061152. Now, this is where I'm stuck. This isn't the answer and I don't know what to do with this number. I'm starting to think this isn't even the right equation. Does the 10mm come into the problem somewhere?