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DaalChawal
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Question itself and options 1 and 3.
Instead of this method If I solve like this I think I'm doing some error. Can you please helpromsek said:So gathering all this up with have
DaalChawal said:and now let's assume all the vowels are together so ways will be = $\frac{4!}{2!}$ = (b)
Permutation refers to the arrangement of a set of objects in a specific order, while combination refers to the selection of a subset of objects from a larger set without regard to order.
The number of permutations can be calculated using the formula n!/(n-r)! where n is the total number of objects and r is the number of objects being arranged. The number of combinations can be calculated using the formula n!/r!(n-r)!, where n is the total number of objects and r is the number of objects being selected.
Yes, repetition can be allowed in permutations and combinations. In permutations, repetition refers to the possibility of an object being used more than once in a specific arrangement. In combinations, repetition refers to the possibility of an object being selected more than once in a subset.
Permutations and combinations are used in various fields such as mathematics, statistics, computer science, and engineering. They are used to solve problems involving probability, counting, and optimization. For example, they can be used to calculate the number of possible outcomes in a game of chance or to determine the number of possible seating arrangements at a dinner party.
One common misconception is that the order of objects does not matter in combinations. In reality, the order of objects does matter in combinations, as changing the order would result in a different combination. Another misconception is that permutations and combinations are only used in mathematics. In fact, they are used in various fields and have practical applications in real life.