(wald) method for calculating curvature

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Discussion Overview

The discussion revolves around the calculation of curvature using the Wald method, focusing on the properties of the Riemann curvature tensor and the notation involved in its expression. Participants explore the implications of antisymmetrization in tensor calculus and the specific coefficients appearing in the curvature equations.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant questions the origin of the coefficients (-2) and (2) in the curvature equation and seeks clarification on the notation used.
  • Another participant explains that brackets around indices indicate antisymmetrization, providing a specific formula for this operation.
  • A further contribution suggests an extension of the antisymmetrization concept to three variables, proposing a formula for handling permutations of indices.
  • Another participant references the curvature tensor's antisymmetry, questioning whether the definition aligns with the antisymmetrization discussed earlier.

Areas of Agreement / Disagreement

Participants express differing views on the interpretation of antisymmetrization and its application to the curvature tensor, indicating that multiple competing perspectives remain without a clear consensus.

Contextual Notes

There are unresolved questions regarding the notation and the implications of antisymmetrization, as well as the specific mathematical steps leading to the expressions discussed.

nulliusinverb
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R[itex]_{a}[/itex][itex]_{b}[/itex][itex]_{c}[/itex][itex]^{d}[/itex]ω[itex]_{d}[/itex]=((-2)[itex]\partial[/itex][itex]_{[a}[/itex][itex]\Gamma[/itex][itex]^{d}[/itex][itex]_{b] }[/itex][itex]_{c}[/itex]+2[itex]\Gamma[/itex][itex]^{e}[/itex][itex]_{[a]}[/itex][itex]_{c}[/itex][itex]\Gamma[/itex][itex]^{d}[/itex][itex]_{<b>}</b>[/itex][itex]_{e}[/itex])ω[itex]_{d}[/itex]

good, me question is about of:

1.- as appear the coefficient (-2) und the (2)?

2.- it is assumed that:
[itex]\partial[/itex][itex]_{[a}[/itex][itex]\Gamma[/itex][itex]^{d}[/itex][itex]_{b]}[/itex][itex]_{c}[/itex]=[itex]\partial[/itex][itex]_{a}[/itex][itex]\Gamma[/itex][itex]^{d}[/itex][itex]_{b}[/itex][itex]_{c}[/itex]+[itex]\partial[/itex][itex]_{b}[/itex][itex]\Gamma[/itex][itex]^{d}[/itex][itex]_{a}[/itex][itex]_{c}[/itex]

also the general form is: (maybe my problem is with the notation)

R[itex]_{a}[/itex][itex]_{b}[/itex][itex]_{c}[/itex][itex]^{d}[/itex]ω[itex]_{d}[/itex]=([itex]\partial[/itex][itex]_{a}[/itex][itex]\Gamma[/itex][itex]^{d}[/itex][itex]_{b}[/itex][itex]_{c}[/itex]-[itex]\partial[/itex][itex]_{b}[/itex][itex]\Gamma[/itex][itex]^{d}[/itex][itex]_{a}[/itex][itex]_{c}[/itex]+[itex]\Gamma[/itex][itex]^{e}[/itex][itex]_{a}[/itex][itex]_{c}[/itex][itex]\Gamma[/itex][itex]^{d}[/itex][itex]_{b}[/itex][itex]_{e}[/itex]-[itex]\Gamma[/itex][itex]^{e}[/itex][itex]_{b}[/itex][itex]_{c}[/itex][itex]\Gamma[/itex][itex]^{d}[/itex][itex]_{a}[/itex][itex]_{e}[/itex])ω[itex]_{d}[/itex]

thank very much!
 
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Brackets around a pair of indices means antisymmetrize. So

[aΓdb]c = ½(∂aΓdbc - ∂bΓdac)
 
Bill_K said:
Brackets around a pair of indices means antisymmetrize. So

[aΓdb]c = ½(∂aΓdbc - ∂bΓdac)

Trying to do the latex is giving me fits. But since we have three variables inside the brackets, shouldn't we write

[tex]f([a,d,b],c) = \frac{1}{6} \left[ f(a,d,b,c) + f(d,b,a,c) + f(b,a,d,c) - f(a,b,d,c) - f(b,d,a,c) - f(d,a,b,c) \right][/tex]

i.e [itex]\frac{1}{n!}[/itex] (even permutations - odd permutations), where n=3?
 
pervect, we have two variables inside the brackets, a and b.

ok... but see the curvature tensor:

R[itex]_{a}[/itex][itex]_{[b}[/itex][itex]_{c}[/itex][itex]_{d]}[/itex]=0

it is definition equal of the tensor antisymmetric in the brackets?

(where it origines ∂[aΓdb]c = ½(∂aΓdbc - ∂bΓdac) ? )


thank very much!
 

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