Wall Cavity Insulation Question?

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Homework Help Overview

The discussion revolves around comparing the thermal performance of different wall construction materials, specifically cavity concrete blocks, brick, and aluminum siding. The original poster expresses confusion about how to begin addressing the problem, which involves calculating the equivalent thickness of walls made from different materials to achieve similar insulation properties.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants suggest starting with the calculation of thermal resistance for the cavity concrete block wall, considering its layered structure. There are discussions about the thermal conductivities of the materials involved and the corresponding calculations for resistance. Questions arise regarding the assumptions made in these calculations and the implications of external influences on thermal performance.

Discussion Status

Participants are actively engaging with the problem, sharing findings on thermal conductivities and discussing the calculations for resistance. Some have provided specific numerical results and are questioning the realism of the thicknesses calculated for aluminum siding. There is a recognition of the need to consider additional factors that may affect thermal performance in real-world scenarios.

Contextual Notes

Participants note that the calculations assume no external influences, which may not reflect real-world conditions. There is an ongoing exploration of the assumptions related to thermal conductivity and the impact of reflection and other attributes on heat conduction.

jake96
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Homework Statement




Hi guys, I have read this question over and over and have no idea where to start, would anyone be able to help.

The Question

Up to 20% of all heat lost in domestic dwellings occurs through walls. Many modern Australian homes are built by constructing walls using ‘cavity concrete blocks’ which have at least a 75 mm air gap or ‘cavity’ as part of their design.

Consider a home built using cavity concrete blocks and compare this to using two other construction materials; brick and aluminium siding. By investigating the heat flow through an external wall,

a) outline the range of assumptions you make.

b) determine, using appropriate calculations to support your answer, the required equivalent
thickness of a home's wall, in order to give the same amount of insulation as a cavity concrete
block wall if the wall is made of
i) brick.
ii) aluminium siding.

c) Discuss comparisons between the individual construction materials.

Thanks


Homework Equations



no idea

The Attempt at a Solution



don't know where to start
 
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They are asking you to compare the thermal performance of three different wall constructions.

Cavity block
Solid Brick
Aluminum (I'm not familiar with this type).

How about you start by calculating the thermal resistance of a cavity concrete block wall ? They are made up of a sandwich of concrete block - air - concrete block. Should be possible to find the data you need (eg typical thickness of each layer and thermal resistance of each material).
 
ok, I've found the thermal conductivity of the four materials
air: 0.024
Aluminium: 205
Brick: 0.15
Concrete: 0.55

and found thickness for concrete block (in accordance to pictures from homework sheet)
concrete (30mm)-air (75mm)- concrete (30mm)

would this be the resistance of the cavity concrete block?
=.03/.55+.075/.024+.03/.55 (thickness/conductivity)
=3.234Km^2/W
 
also using a wall of 1mx1m so its not a hassle in calculations
 
jake96 said:
ok, I've found the thermal conductivity of the four materials
air: 0.024
Aluminium: 205
Brick: 0.15
Concrete: 0.55

and found thickness for concrete block (in accordance to pictures from homework sheet)
concrete (30mm)-air (75mm)- concrete (30mm)

would this be the resistance of the cavity concrete block?
=.03/.55+.075/.024+.03/.55 (thickness/conductivity)
=3.234Km^2/W
Good. Now, how thick would these other individual materials have to be to give this same resistance?

Chet
 
Brick
3.234=x/.15
=485mm

aluminium
3.234=x/205
=663m

this seems a little extreme for the aluminium
 
jake96 said:
Brick
3.234=x/.15
=485mm

aluminium
3.234=x/205
=663m

this seems a little extreme for the aluminium
Well, aluminum has a very high thermal conductivity.

Chet
 
so these sort of calculations would be correct considering no other outside influence,

in reality this value would be much lower due to reflection and other attributes
 
jake96 said:
so these sort of calculations would be correct considering no other outside influence,

in reality this value would be much lower due to reflection and other attributes


What kind of reflection is involved with heat conduction?

Chet
 
  • #10
What formula did you use to find the thermal conductivity?
 

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