How do I calculate the temperature at different layers within a cavity wall?

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Homework Help Overview

The discussion revolves around calculating the temperature at different layers within a cavity wall, specifically focusing on a wall composed of brick, cork, and wood with given thermal conductivities and temperature conditions.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the temperature at the interfaces between the layers of materials using a formula for heat transfer. Some participants suggest applying thermal resistance concepts to find the surface temperatures at the interfaces.

Discussion Status

Participants are engaged in exploring the calculations needed to determine the temperatures at the interfaces. Guidance has been offered regarding the use of thermal resistance in the calculations, indicating a productive direction in the discussion.

Contextual Notes

The original poster expresses difficulty in calculating the temperatures at specific interfaces, indicating a need for clarification on the application of thermal resistance in their approach.

ingram010
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Hi all

I have a revision question I am having some trouble with

A cold room has a wall measuring 5.2m by 2.5m. The wall is constructed of 120mm thick brick on the inside, a cork layer 80mm and a 30mm layer ow wood in the outside. the inside temperature is -4ºC and the outside temperature is 70ºC.

The thermal conductivities of the materials are:-

Brick,0.9Wm^-1K^-1, Cork, 0.04Wm^-1K^-1, and wood, 0.17Wm^-1K^-1


The formula for calculating for the rate of heat transfer through all the layers is:-

-Area/ (x1/k1) + (x2/k2) + (x3/k3) x (T1- T2)

so -13/ (0.12/0.9) + (0.08/0.04) + (0.03/0.17) x (-4 - 70) = 416.485 watts.

I am having a problem with the calculating the temperatures at the brick/cork and cork/wood interfaces.

If anyone could help I would be very grateful

Kindest regards

John


The Attempt at a Solution

 
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Apply:

qT = Ts1 - Ts2 / Rs12

where,

qT = total heat transfer rate (you already calculated).
Ts1 = surface temperature at interface 1
Ts2 = surface temperature at interface 2
Rs12 = thermal resistance between surface 1 & 2 (for example: x1/k1)

So start at the surface with the known temperature (call it surface 1), and figure:

Ts2 = Ts1 - qT / Rs12

and work your way to the other end.
 
Thanks edgepflow

much appreciated
 
thank you a lot this was the information i have been searching for last 2 days
 

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