Water Chemistry Cation Determination

Click For Summary
SUMMARY

The forum discussion focuses on determining the missing cation (B) in a water sample containing various ions, including K+, Sr+2, Ca+2, Mg+2, HCO3-, SO4-2, NO3-, Cl-, and CO3-2. The Total Dissolved Solids (TDS) is measured at 1397 mg/L. The user identifies that the missing ion can be either Fe+2, Ba+2, Cd+2, or HPO4-2, and concludes that using the alkalinity of HCO3- as 230 mg/L as CaCO3 leads to identifying the missing ion as Cd+2, which balances both mass and charge requirements. The discussion emphasizes the importance of converting ion concentrations to electric charge for accurate determination.

PREREQUISITES
  • Understanding of water chemistry and ion concentrations
  • Knowledge of equivalent weights and normality calculations
  • Familiarity with Total Dissolved Solids (TDS) measurement
  • Basic principles of charge balance in chemical solutions
NEXT STEPS
  • Research methods for calculating equivalent weights in water chemistry
  • Learn about charge balance calculations in aqueous solutions
  • Study the implications of Total Dissolved Solids (TDS) on water quality
  • Explore the identification of unknown ions using mass and charge balance techniques
USEFUL FOR

Water chemists, environmental scientists, and anyone involved in water quality analysis will benefit from this discussion, particularly those focused on cation determination and charge balance in water samples.

biker.josh07
Messages
5
Reaction score
0
I'm having some trouble with this one

A water sample contains the following ions (all in mg/L except HCO3-)

K+=70, Sr+2=20, Ca+2=180, Mg+2=80, HCO3-=230 mg/L as CaCO3-2, SO4-2=164, NO3-=37, Cl-=400, CO3-2=35, and B=?? has a valence number of 2 but the sign is unknown.

TDS(Total Dissolved Solids)=1397 mg/L

Assume the water is balanced, identify the missing ion B as being Fe+2, Ba+2, Cd+2 or HPO4-2.

So I worked out the Equivalent Weights and converted the concentrations to the respective normalities.Then I added up all the positive and negative normalities and found a difference of 3.21meq/L favouring the anions.

My problem is when I work out the mass concentration for the B ion I convert the HCO3- to its mass concentration 280.6 mg/L rather than using its alkalinity of 230 mg/L as CaCO3.However this gives me the wrong answer with a molecular weight of 81.2 which doesn't correspond to anything but I get the right answer if I use 230 and it works out to be Cd+2 because you get a molecular weight of 112.8.so yeah this doesn't make sense.
 
Physics news on Phys.org
Try converting your cations and anions into electric charge as well. Think of balancing the moles of positive charge and moles of negative charge. For example, if you have 100 mL solution of potassium chloride of concentration 0.050 meq/L, then you will have 0.005 meq of positive charge and 0.005 meq of negative charge. Do that for all the ions and anions to determine the excess charge in moles, equivalents, meq or whatever.

Only one cation will meet the double requirement of providing both the mass (from the TDS number) and the missing charge to exactly counter the excess charge.
 
Last edited:

Similar threads

  • · Replies 9 ·
Replies
9
Views
6K
  • · Replies 2 ·
Replies
2
Views
39K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 2 ·
Replies
2
Views
10K
  • · Replies 1 ·
Replies
1
Views
8K
Replies
17
Views
8K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
15K
  • · Replies 4 ·
Replies
4
Views
11K
Replies
5
Views
9K