Energy Require from water-steam

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SUMMARY

The energy required to change one quarter of 8.0 kg of water at 25°C into steam is calculated using the formula Q = mcΔT + mL_v, where m is the mass of water, c is the specific heat capacity, ΔT is the temperature change, and L_v is the latent heat of vaporization. The specific calculations yield Q = 2,520,000 J for heating the water to 100°C, and an additional 4,600,000 J for vaporizing 2.0 kg of water, resulting in a total energy requirement of 7,120,000 J. The discussion clarifies the importance of using the correct latent heat value for vaporization rather than fusion.

PREREQUISITES
  • Understanding of specific heat capacity (c) and its units (J/(kg·°C))
  • Knowledge of latent heat of vaporization (L_v) and its value (2,300,000 J/kg)
  • Ability to perform basic algebraic calculations involving mass and energy
  • Familiarity with temperature conversion and the Celsius scale
NEXT STEPS
  • Study the concept of latent heat and its applications in phase changes
  • Learn about specific heat capacities of various substances
  • Explore thermodynamic principles related to energy transfer in heating and phase changes
  • Practice solving problems involving energy calculations for different states of matter
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone looking to understand energy calculations in phase changes of water.

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Homework Statement


How much energy is required to change one quarter of 8.0kg of water at 25°C into steam.




Homework Equations


I get confused to exact what equation to use to figure out the energy required.

I *think* it would be this one:
Q_{t}=M_{water}C_{water}\DeltaT_{water} + .25(M_{water})L_{f}


The Attempt at a Solution


When I do the math, I come up with a ridulous number that makes no sense. I try and try to understand but I can't.

:/.
 
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What are the values of the constants are you using? What value are you getting?
 
Would it be:

Q=mc\Deltat
Q=(8.0kg)(4200J/(kg·°C))(100°C-25°C)
Q=2 520 000

Then since your finding a a quater of it would you then muliply by .25

2520000x.25

=630000J

It seems to easy since the question is worth 5 marks, it feels like I'm missing a step or something :/
 
It boils down to (pun!) whether you are expected to raise all 8.0 kg of water to 100° and then transform 1/4 of it to steam, or whether you are to take 1/4 of 8.0 kg of water and raise its temperature to 100° and then transform it to steam.

Your value for Q looks okay for raising the 8.0 kg of water to 100°. How much additional energy will it take to convert 1/4 of that water at 100° to steam at 100°?
 
I loved the pun, I actually had a giggle with that one!

Right now I'll have to find the mass of the steam itself!
Q=

To find the additional energy would I use the equation that I initially posted (would I use latent fusion or Latent vaporiztion)?

BUT I don't know the mass of the steam nor do I know the Energy, so I have NO Idea where to go next :(:(

(it sucks trying to teach yourself everything from Grade 11 math when you've been out of high school for 6 years :/)
 
The mass is just 1/4 of 8.0 kg. You want to vaporize this mass of water, so you'd use the latent heat of ______?
 
Vaporization since you want to vaporize the mass.

So with that being said

Q=(8.0kg)(4200J(kg·°C)(100°C-25°C)+.25(8.0kg)(2300000)
Q=2520000 + 4600000
Q=7120000J
 
Looks good!
 
Thank you so much!
 

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