How Does Complex Epsilon Influence Wave Propagation and Attenuation?

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SUMMARY

The discussion centers on the influence of complex permittivity (epsilon, ε) on wave propagation and attenuation in a medium. It establishes that the ratio of decay length to wavelength is approximately Re(ε)/Im(ε) when the decay length significantly exceeds the wavelength. Participants explore the relationship between the wave vector (k), wavelength (λ), and refractive index (N), with N defined as N=√(ε/ε0). The conversation highlights the importance of understanding the real and imaginary components of ε for accurate wave analysis.

PREREQUISITES
  • Complex permittivity (ε) and its components
  • Wave propagation in electromagnetic theory
  • Refractive index (N) and its calculation
  • Exponential wave representation (E=Aexp(kr-wt))
NEXT STEPS
  • Study the derivation of the relationship between decay length and wavelength in complex media
  • Learn about the implications of complex refractive indices on wave behavior
  • Explore the mathematical representation of electromagnetic waves in various media
  • Investigate the physical significance of the real and imaginary parts of permittivity
USEFUL FOR

Physicists, electrical engineers, and researchers in optics and materials science who are analyzing wave behavior in complex media and seeking to understand the effects of complex permittivity on wave propagation and attenuation.

mathman44
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Consider a wave propagating in a medium with complex epsilon (e).

Show that the ratio of decay length to wavelength is roughly Re(e)/Im(e)
when the decay length is long compared to the wavelength.

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I could attempt this if I knew where to start... not much help, but could anyone offer a hint?
 
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A plane electromagnetic wave of angular frequency ω propagates along the x-axis in a medium of refractive index N. Write out the wave in the exponential form.

The refractive index is N=√(ε/ε0). If ε is complex, so is N.

ehild
 
Well a plane wave for an em wave is

E=A\exp{(kr-wt)}

I'm just not seeing how to proceed from here.
 
How is related k to the wavelength? The wavelength in the medium to the refractive index? The refractive index to epsilon?

ehild
 
Last edited:
Hi. We have k=\frac{2pi}{\lambda} = \frac{2*pi*n}{\lambda_o} = \frac{2*pi*\sqrt{\epsilon}}{\lambda_o}

But of course epsilon has real and complex parts...

The ratio of the wavelength to the decay length is lambda / (1/imaginary part of k) :S
 
Do you know the imaginary part of k?

ehild
 

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